3 years ago

Help. I got it wrong and have no clue how to get to the right answer!

1 answer:

7 0

$\bf 2x+\sqrt{4x^2}+\sqrt[3]{8x^3}\qquad 
\begin{cases}
4\to 2^2\\
8\to 2^3
\end{cases}\qquad thus
\\\\\\
2x+\sqrt{2^2x^2}+\sqrt[3]{2^3x^3}\implies 2x+\sqrt{(2x)^2}+\sqrt[3]{(2x)^3}
\\\\\\
2x+2x+2x=\boxed{6x}$

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