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Rudik [331]
4 years ago
6

How do you solve this?

Mathematics
1 answer:
liberstina [14]4 years ago
3 0

Answer:

The answer is

<h2>{13}^{3}</h2>

Step-by-step explanation:

<h3>( {13})^{2}(  {13})^{ - 4} ( {13})^{5}</h3>

To solve the expression , use the rules of indices

Since the bases are the same and are multiplying we add the exponents

That's

<h3>{a}^{x}  \times  {a}^{y}  \times  {a}^{z}  =  {a}^{x + y + z}</h3>

So we have

<h3>( {13})^{2}(  {13})^{ - 4} ( {13})^{5}   =  {13}^{2 - 4 + 5}  \\  =  {13}^{ - 2 + 5}</h3>

We have the final answer as

<h3>{13}^{3}</h3>

Hope this helps you

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Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
-Dominant- [34]

Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)

\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

\dfrac{\sin(\beta)}{\cos(\beta) }

Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

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2 years ago
In San Diego the average cost of gas is $4.15 per gallon. If a car has a fuel efficiency of 24 miles per gallon and the owner of
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Answer:

$25.94

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6.25 × 4.15 = 25.9375

25.94

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3 years ago
Which of the following words correctly describe a triangle with two 45 angles?
Tom [10]
Well, first let's identify which answers are incorrect, then it will be easier to figure out which are correct.

A. Equilateral: An equilateral triangle is a triangle with 3 equal sides. Since there are 180 degrees in a triangle, an equilateral triangle would have three sides of 60 degrees, and none of 45 degrees. Answer? Incorrect.

B. Isosceles: An isosceles triangle has two sides that are equal. 45 and 45 are equal, therefore, this answer is: Correct!

C. Scalene: A scalene triangle has three unequal sides, therefore, this answer is incorrect.

D. Obtuse: An obtuse triangle has one angle that is more than 90 degrees, therefore, since 45 and 45 equal 90 already, this answer is: incorrect.

E. Right: A right triangle has one right angle (angle that equals 90 degrees) since 45 + 45 = 90, and 90 + 90 = 180, this answer is: Correct!

F. Equiangular: This last choice is practically the same as the first, therefore the answer is: incorrect.

The two correct answers are: B Isosceles, and E Right!
4 0
4 years ago
Read 2 more answers
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