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3 years ago

What is 1 2over5 plz i need help

Mathematics

2 answers:

emmainna [20.7K]3 years ago

7 0

The person on the top is right

Yuri [45]3 years ago

3 0

Answer:

12/5 also 2.4

Step-by-step explanation:

12 divided by 4 = 2.4

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Please answer quickly, more might be coming soon. 50 Points!

Brut [27]

Answer:

2) ∠SDH and ∠SDT are right angles because SD ⊥ HT.

3) $\bar{SH}\cong \bar{ST}$ as it is given in the question.

4) $\bar{SD}\cong \bar{SD}$ is the reflexive property.

5) ΔSHD ≅ ΔSTD by RHS congruency.

Step-by-step explanation:

Given in the question:

$\bar{SH}\cong \bar{ST}\\\bar{SD}\perp \bar{HT}$

In ΔSHD and ΔSTD

$\bar{SH}\cong \bar{ST}$ (Given)

$\angle SDH\cong \angle SDT=90^o$ (SD ⊥ HT)

$\bar{SD}\cong \bar{SD}$ (Common)

Therefore, $\Delta SHD\cong \Delta STD$ (By RHS rule)

Reflexive property of congruency is defined as the property in which something is equal to itself. Hence, the reflexive property of these two triangles is $\bar{SD}\cong \bar{SD}$

5 0

3 years ago

in the problem 10 - 4=6 what is the correct term for the number 4? a) product b) subtrahend c) difference d) minuend

balu736 [363]

The answer is B. Subtrahend.

5 0

3 years ago

Read 2 more answers

Find the cdf F(x) associated with each of the following probability density functions. Sketch the graphs of f(x) and F(x).

wolverine [178]

Answer:

See steps below

Step-by-step explanation:

$\bf f(x)=3(1-x)^2\;(0$

$\bf F(x)=\int_{0}^{x}f(t)dt=\int_{0}^{x}3(1-t)^2dt=3\int_{0}^{x}(1-t)^2=1-(1-x)^3$

The cdf associated with f is

$\bf \boxed{F(x)=1-(1-x)^3}$ for 0<x<1

<h3>See picture 1 </h3>

The median is a point x such that

F(x) = ½

so, the median is

$\bf 1-(1-x)^3=1/2\rightarrow (1-x)^3=1/2\rightarrow \boxed{x=1-\sqrt[3]{2}}$

The 25th percentile equals the 1st quartile and is a point x such

F(x) = ¼

and the 25th percentile is

$\bf 1-(1-x)^3=1/4\rightarrow (1-x)^3=3/4\rightarrow \boxed{x=1-\sqrt[3]{3/4}}$

$\bf f(x)=\frac{1}{x^2}\;(1$

$\bf F(x)=\int_{1}^{x}f(t)dt=\int_{1}^{x}\frac{dt}{t^2}=1-\frac{1}{x}$

The cdf associated with f is

$\bf \boxed{F(x)=1-\frac{1}{x}}$ for x>1

<h3>See picture 2 </h3>

The median is

$\bf 1-\frac{1}{x}=\frac{1}{2}\rightarrow \boxed{x=2}$

The 25th percentile is

$\bf 1-\frac{1}{x}=\frac{1}{4}\rightarrow \boxed{x=4/3}$

f(x) = 1/3 for 0<x<1 or 2<x<4

$\bf F(x)=\int_{0}^{x}\frac{dt}{3}=\frac{x}{3}\;(0$

$\bf F(x)=\frac{1}{3}+\int_{2}^{x}\frac{dt}{3}=\frac{1}{3}+\frac{x-2}{3}=\frac{x-1}{3}\;(2$

The cdf associated with f is

$\bf F(x)=\frac{x}{3}$ for 0<x<1

$\bf F(x)=\frac{x-1}{3}$ for 2<x<4

<h3>See picture 3 </h3>

The median is

$\bf \frac{x-1}{3}=1/2\rightarrow x=1+3/2\rightarrow \boxed{x=5/2}$

The 25th percentile is

$\bf \frac{x}{3}=1/4\rightarrow \boxed{x=3/4}$

4 0

4 years ago

Doug is going to ride his bicycle 3 , 000 miles across the United States, from coast to coast. He wants to choose the route that

kondor19780726 [428]

Answer:

imma give you the pdf

Step-by-step explanation:

7 0

3 years ago

Parallelogram ABCD has vertex coordinates A(0, 1), B(1, 3), C(4, 3), and D(3, 1). It is translated 2 units to the right and 3 un

Ivenika [448]

Answer: The correct option is (C). (-2, 2).

Step-by-step explanation: Given that the co-ordinates of the vertices of parallelogram ABCD are A(0, 1), B(1, 3), C(4, 3), and D(3, 1). The parallelogram ABCD is translated 2 units to the right and 3 units down and then rotated 180 clockwise around the origin.

We are to find the co-ordinates of the vertex A after the transformation.

We know that if the point (x, y) is translated a units right and b units down, then its new co-ordinates will be (x + a, y - b).

So, the co-ordinates of point A after translation of 2 units to the right and 3 units down are

(0 + 2, 1 - 3) = (2, -2).

Now, a rotation of 180° clockwise will change the co-ordinates (x, y) to (-x, -y).

Therefore, the final co-ordinates of point A are

(2, -2) ⇒ (-2, 2).

Thus, the new co-ordinates of A are (-2, 2).

Option (C) is CORRECT.

8 0

4 years ago