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3 years ago

Subtracting integers is the same as adding what?

Mathematics

2 answers:

zysi [14]3 years ago

5 0

Answer:

Subtracting (negative) integers is the same as subtracting positive numbers.

tatuchka [14]3 years ago

3 0

Answer:

Subtracting negative integers is the same as adding the absolute value of that number.

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Help! Please! !!!!!!!!!!!!

asambeis [7]

Answer:

Step-by-step explanation: what is your question

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2 years ago

Solve for x. x−1/4=3/8

valentinak56 [21]

x=5/8 is the correct answer. First you had to simplify from both sides of equation, and it gave us, $x+\frac{-1}{4}=\frac{3}{8}$ . Then you add 1/4 from both sides of equation, and it gave us, $x+\frac{-1}{4}+ \frac{1}{4}= \frac{3}{8}+ \frac{1}{4}$ . And it gave us the answer is x=5/8 is the final answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

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3 years ago

AC is a straight segment as shown in the diagram below. If the distance between points A and C is 67 miles, determine the distan

GuDViN [60]

Answer:

Step-by-step explanation:

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2 years ago

The width of a rectangle is the length minus 6 units the area of the rectangle is 27 units

AleksandrR [38]

Answer:

length = 9 units

Step-by-step explanation:

l = length

n - 6 = width

A = n(n - 6)

A = n² - 6n

27 = n² - 6n

n² - 6n - 27 = 0

(n + 3)(n - 9) = 0

n = -3, n = 9

length must be 9 because it cannot be a negative value

6 0

2 years ago

A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the

mart [117]

Answer:

0.1552

Step-by-step explanation:

Hi!

Give a random person, lets call:

D = the person has the disease

¬D = the person doesnt have the disease

T = the test on this person is positive (detects the disease)

¬T = the test on this person is negative

We are give the conditional probabilities:

P(T | D) = 0.9

P(¬T | ¬D) = 0.9

P(D) = 0.02

From those we know that:

P(T | ¬D) = 0.1

P(¬T | D) = 0.1

We must find P(D | T). For that we use Bayes theorem:

$P(D|T) = \frac{ P(T|D)P(D)}{P(T|D)P(D) +P(T| \neg D)P(\neg D) }$

$P(D | T) = \frac{0.9*0.02}{0.9*0.02 + 0.1*0.98} = 0.1552$

6 0

3 years ago