<span>Answer:
I assume you're looking for a time-weighed average rather than just the [H(0) + H(60)]/2 average.
Havg = (1/60)â«[20+980e^(-0.1t)]dt (evaluated from 0 to 60)
Havg = (1/60)[20t - 98e^(-0.1t)] evaluated from 0 to 60
Havg = (1/60)[20(60) - 98e^(-6) - 20(0) + 98e^(0)] = 1297.76/60 = 21.629 °C</span>
The first, third, and fourth choices are functions. A relation is a function when x does not repeat. For the second choice, -4 repeats. Therefore, it is not a function. The other choices do not repeat an x-coordinate, so they are correct.
Hi there!

∠C = 40° and triangle ABC is isosceles, therefore:
∠C = ∠A = 40°
Angles in a triangle sum up to 180°, so:
180 = 40 + 40 + ∠A
180 = 80 + ∠A
100 = ∠A
Thus, arc CB has a measure of 100°.
<span><span>−<span>a<span><span>4</span><span></span></span></span>−4 <span>a<span>2 is the answer for your question. </span></span></span><span><span></span></span></span>
We are given : The cost of tools for building wind chimes = $130.
Cost of material for each wind chime = $10.
We need to find the total cost of making 100 wind chimes.
Please note : $130 is the fix cost and $10 is the variable cost of each wind chime.
<em>In order to find the cost of 100 wind chimes, we need to multiply 100 by cost of making one wind chime and add the fix cost for tools for building wind chimes.</em>
Therefore, total cost of making 100 wind chimes = 10×100 + 130
= 1000+130
=1130.
<h3>Therefore, the total cost to make 100 wind chimes is $1130.</h3>