The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Answer:
- -1
- 0
Step-by-step explanation:
1. cos(π) = -1
2. sin(π) = 0
_____
It is useful to memorize the table below.
D/20=20/15
d=400/15
d=80/3
d=26 2/3 miles
Answer:
$110,080
Step-by-step explanation:
This is an arithmetic sequence because each new term is obtained by adding $5000 to the preivous term.
The general formula for such an arithmetic series is
a(n) = $80,000 + ($5,000)(n - 1)
and so in his 23rd year Jason would make
a(23) = $80,000 + ($5,000)(23 - 1), or
$110,080
Answer:
ican you show the chart? then ill edit this to the answer
Step-by-step explanation: