<h2>
Answer: <u><em>
1</em></u></h2>
<u />
Step-by-step explanation:
![\sqrt[4]{81} -2\\=3-2 \\=1](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81%7D%20-2%5C%5C%3D3-2%20%5C%5C%3D1)
For a), this is clearly a given as it is literally to the right of where it says “Given:”
For b), since ON bisects ∠JOH, this means that it splits it into two separate angles - JON and HON, which are similar due to that bisects mean that it splits it equally into two halves
For c), since NO is the same thing as NO, it is equal to itself
For d), since AAS (angle-angle-side) congruence states that if there are two angles that are congruent (proved in a) and b) ) as well as that a side is congruent (proved in c) ), two triangles are congruent
For e), since two triangles are congruent, every side must have one side that it matches up to in the other triangle. As the opposite side of angle H is JO and the opposite side of angle J is OH, and ∠J=∠H, those two are congruent. As JN and HN are the two sides left, they must be congruent.
Feel free to ask further questions!
We'll represent Louise's, Tammy's, Delores's, and Sheryl's point values with 
, 
, 
, and 
respectively since each one is 1 point more than the last.
Add all of these values up and set it all equal to 
.
Now, simplify.
Subtract 
on both sides.
Divide both sides by 
.
Since Louise's score is , the answer is 
.
<h3>Double-checking</h3>
To verify our answer, add the point totals , 
, 
, and 
.
This equals , so we can be sure the answer is correct.
Answer:
3rd choice
Step-by-step explanation:
(7y^6)(2y^-4)^2
= (7y^6)(4y^-8)
Calculate:
(7y^6) * (4y^-8)
28y^-2
Express with a positive exponent:
28 * 1/y^2
Answer: y+44+68=180
Step-by-step explanation: y+44 and 68 are complementary angles so they add to equal 180
