Answer:
y = x - 5
Step-by-step explanation:
Equation of any two parallel lines differ only by a constant.
Therefore, the equation of the line parallel to 
would be ax + by + c₂ = 0.
The equation of the line parallel to 
should be equal to
x - y + c = 0.
Since, a point intersecting the line is given this means that the line passes through this point. This can be used to determine the value of c.
⇒ 3 -(-2) + c = -5 + c = 0
⇒ c = - 5.
Substituting we get: x - y - 5 = 0
⇒ y = x - 5 is the required equation of the line.
The following
statements are true by definition:
The side
opposite ∠L is NM.
The side
opposite ∠N is ML.
The side
opposite to the angle should not contain any letter of that side.
<span>The following
statements are not essentially true because we have no idea if triangle LNM
is a right triangle (if it is, then we do not know what the hypotenuse is):</span>
The
hypotenuse is NM.
The
hypotenuse is LN.
<span>The following
statements are not true:</span>
The side
adjacent ∠L is NM.
The side
adjacent ∠N is ML.
They are not
true because the side adjacent to an angle should have its letter on the side.
For example, the side adjacent to ∠L should be LN or LM and
for ∠N it should be NM or NL.
<span> </span>
The pricing of the boxes seems to be consistently 2.40 per box. Ethan's cost is
.. 52.80 = 2.40 * (# of boxes)
.. 52.80/2.40 = (# of boxes)
.. 22 = # of boxes
Ethan has bought 22 boxes for 52.80.
Answer:
4 feet
Step-by-step explanation:
Because if she used 1 feet of ribbon for 3 bows you need to multiply by 4 to 1 foot and you will get 12 bows
Answer: we can get the sequence of reasons with help of below explanation.
Step-by-step explanation:
Here It is given that, line segment BD is the perpendicular bisector of line segment AC. ( shown in below diagram)
By joining points B with A and B with C ( Construction)
We get two triangles ABD and CBD.
We have to prove that : Δ ABD ≅ Δ CBD
Statement Reason
1. AD ≅ DC 1. By the property of segment bisector
2. ∠BDA ≅ ∠ BDC 2. Right angles
3. BD ≅ BD 3. Reflexive
4. Δ ABD ≅ Δ CBD 4. By SAS postulate of congruence
