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kogti [31]
2 years ago
6

If a boat depreciates in value according to the simple interest formula Y=20,000(.92)^2 find the rate of decay. Write as a perce

ntage.
Mathematics
2 answers:
RUDIKE [14]2 years ago
8 0

Answer:

16%

Step-by-step explanation:

A boat depreciates in value according to the simple interest formula:

Y=20,000*(0.92)^{2} = 16,928

From the above exponential function, we can see that:

The boat depreciates with the base number is: 0.92 and the initial value is 20,000 at the beginning,

So  the rate of decay which can be written as a percentage:  

1 -  The value after 2 units of time / the initial value

= 1- (16,928 / 20,000)

= 1  - 0.84

= 0.16

= 0.16*100% = 16%

zhenek [66]2 years ago
5 0

Answer:

$28,000

Step-by-step explanation:

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3 years ago
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Answer:

x=8

z = 115

Step-by-step explanation:

65 and 13x - 39 are vertical angles so they are equal

65 = 13x - 39

Add 39 to each side

65+39 = 13x - 39+39

104 = 13x

Divide each side by 13

104/13 = 13x/13

8 =x

65 and z are supplementary angles because they form a straight line.  This means they add to 180

65+z = 180

Subtract 65 from each side

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3 years ago
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Which property of multiplication is shown 2 questions
8_murik_8 [283]
The property that is shown is called the zero property.
7 0
2 years ago
Explain what a polynomials is and identify the different parts of a polynomial.
Wewaii [24]
Question 1 
Polynomials are expressions that include constants and variables. We can use addition, subtraction, multiplication and we can use exponents but only with positive integers. In polynomials, you cannot use division by a variable. This means that you can't have terms like:
\frac{a}{x^n}
Where a is constant, x is a variable and n is a positive integer.
Here is an example of a polynomial:
5x^3+3x^2+\frac{x}{2}+9
x would be is a variable, please keep in mind that you can have polynomials with more than one variable. Numbers before variables are called constants.
Here are some example of constants:
2;2/3;\pi;\sqrt(2)
And we also have exponents. Exponents are numbers written in the upper-right corner of a variable. These must be positive integers.
Question 2
We can name polynomials based on their degree and number of terms.
A degree is largest exponent. Examples:
x^3+2x+3; degree=3\\ x^2+2; degree=2\\ 21;degree=0
You can have polynomial without variable.
Here is a chart showing you special names for polynomials based on their degree:
0\ constant\\ 1 \ linear\\ 2 \ quadratic\\ 3 \ cubic\\ 4 \ quartic\\ 5 \ quintic\\
There are special names for polynomials with 1, 2, 3 terms. These are monomial, binomial, trinomial. For polynomials that have more than 3 terms, we simply say polynomial of n terms.
Question 3
When adding or subtracting polynomials we simply subtract/add like terms.
Like terms are those that have the same exponent. Here is an example:
4x^3+2x^2+x+5\\ x^4 -x^3+3x^2\\
Let us add these two polynomials:
4x^3+2x^2+x+5\\ x^4 -x^3+3x^2\\ x^4+(4x^3-x^3)+(2x^2+3x^2)+x+5=x^4+3x^3+5x^2+x+5
Question 4
Foil stands for First, Outer, Inner, Last.
Foil can be used only to multiply two binomials( polynomials that have 2 terms). 
Here is an example:
(2x+3)(x-2)= (2x\cdot x) (First)+(2x\cdot (-2)) (Outer)+(3\cdot x)(Inner)\\ + (3\cdot (-2)) (Last);\\ (2x+3)(x-2)=2x^2-2x+3x-6=2x^2+x-6
Question 5
First special case is square of a sum/difference. This happens when we want to multiply two identical polynomials. Example:
(x+2)(x+2)\\ (x^2-x)(x^2-x)
Second special case is a product of a sum and a difference. 
Here is an example:
(x-2)(x+2)\\
(x^2-x)(x^2+x)
Question 6
For these two special cases we can use following formulas:
(a\pm b)^2=a^2 \pm2ab+b^2\\
(a+b)(a-b)=a^2-b^2
Let me explain first formula:
(x+3)^2=x^2+6x+9\  Using the formula\\
(x+3)(x+3)=x^2+3x+3x+9=x^2+6x+9;Using FOIL

(x-3)^2=x^2-6x+9\ Using the formula\\ (x-3)(x-3)=x^2-3x-3x+9=x^2-6x+9;Using FOIL
Here is an example for second formula:
(x-3)(x+3)=x^2-9=x^2-(3)^2; Using formula\\
(x-3)(x+3)=x^2+3x-3x-9=x^2-9=x^2-(3)^2
You can see that we get the same result, so when you have these special cases you can use formulas as a schortcut.

8 0
3 years ago
Help me plz, I need the solutions of all of them. Thank you very much
arsen [322]

Answer:

  • Question 6: 1/4
  • Question 7: 3/20
  • Question 8: 13/20
  • Question 9: They are not independent.

Explanation:

<u />

<u>1. Build a two-way frequency table filling only the initial information:</u>

                                   Take AMS1303   No take AMS1303   Total

Take FIN1001                         25                                                40

No take FIN1001                    

Total                                       50                                               100

<u />

<u>2. Complete the table calculating the missing values by differences:</u>

  • Take AMS1303 only: 50 - 25 = 25
  • No take AMS1303 and take FIN1001: 40 - 25 = 15
  • No take AMS1303: 100 - 50 = 50
  • No take FIN1001: 100 - 40 = 60
  • No take AMS and no take FIN: 60 - 25 = 35

                                   Take AMS1303   No take AMS1303   Total

Take FIN1001                         25                      15                      40 (F)

No take FIN1001                    25                      35                     60  

Total                                       50                      50                   100 (S)

                                              (M)

<u />

<u>3. Question 6: Probability that the chosen student takes only AMS1303</u>

  • P(M) - P(M∩F) = 50/100 - 25/100 = 25/100 = 1/4

<u>4. Question 7: Probability that the chosen student takes only FIN1001</u>

  • P(F) - P(M∩F) = 40/100 - 25/100 = 15/100 = 3/20

<u>5. Question 8: Probability that the chosen student takes AMS1303 or FIN1001</u>

  • P(MUF) = P(M) + P(F) - P(M∩F) = 50/100 + 40/100 - 25/100 = 65/100 = 13/20

<u />

<u>6. Question 9: Is the event of selecting a student taking AMS1303 independent of the event of selecting a student taking FIN1001?</u>

We will use contidional probability. Two events are independent only if the probability of one event is equal to the probability is the same as the  probability of the event given that the other event occurs.

  • Is P(M|F) = P(M) ?

P(M|F) = P(M∩F) / P(F) = (25/100) / (40/100) = 25/40 = 5/8

But P(M) = 50/100 = 1/2

Then, P(M|F) ≠ P(M) , therefore they are not independent

Also, you might determine:

  • Is P(F|M) = P(F)?

P(F|M) = P(M∩F) / P(M) = (25/100) / (50/100) = 25/50 = 1/2

P(F) = 40/100 = 2/5

Again, of course, P(F|M) ≠ P(F), meaning that they are not independent.

5 0
3 years ago
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