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zepelin [54]
3 years ago
8

Hi what is the answer

Mathematics
2 answers:
julia-pushkina [17]3 years ago
8 0

Answer: 48 sq. cm.

Step-by-step explanation:

Area = l x w

= 12 x 4 = 48 sq. cm.

Elodia [21]3 years ago
3 0

Answer:

48 cm^{2}

Step-by-step explanation:

Use the formula for the area of rectangle.

A=lw

Area = A

Length = l

Width = w

A=12 \times 4

A= 48

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0.4/0.01=40 how does the quotient relate to divide
valkas [14]
Quotient  is the answer of the division
0.4/0.01 = 40 x 10 = 4/0.1 = 40 x 10 = 40/1 = 40
8 0
3 years ago
How do you do this problem?
faust18 [17]

The volume of the original cylinder is

... V = π·r²·h

For r=1 and h=1, this is

... V = π·1²·1 = π

For the new cylinder, the volume is 1.089 times that amount.

... V = 1.089π = π·1.1²·(1-k)

... 1.089/1.21 = 1-k

... k = 1 - 1.089/1.21 = 1 - 0.9 = 0.1 = 10%

The appropriate choice is (B) 10.

7 0
3 years ago
Read 2 more answers
Solve this equation: y-3x+15=10
Jlenok [28]

Answer:

10=10

Step-by-step explanation:

y-3x+15=10

y=3x-15+10

y=3x-5

subtitute y=3x-5 in the above equation:

3x-5-3x+15=10 (3x will be eliminated with -3x)

-5+15=10

10=10

(i hope this is the way you want the answer but at least I think it is correct)

3 0
3 years ago
Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

8 0
3 years ago
Does anyone know what the code is Ive been stuck on this for like ever.
timama [110]

Answer:

Binary code

Step-by-step explanation:

Code is a word or a symbol which is not disclosed to everyone and is considered as secretive. There are various codes which are required to run a software in order to minimize the risk of piracy. These codes are binary codes or java codes. These are complex so that not everyone can crack it.

3 0
3 years ago
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