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coldgirl [10]
3 years ago
7

Terry just bought a used car with only 28,500 miles on it and it cost $8,200. Every year Terry expects to put another 14,000 mil

es on the car. Unfortunately, the car’s value will depreciate by 15% per year. How much will the car be worth when it has 100,000 miles on it? Explain your work.
Mathematics
1 answer:
VikaD [51]3 years ago
3 0
It will take (100 -28.5)/14 ≈ 5.107 years to get to 100,000 miles. In that time the car will depreciate by a factor of 0.85^5.107, about 0.43605. The value at that time will be
.. $8200*0.43605 ≈ $3706

_____
The difference between 100k miles and 28.5k miles is 71.5k miles. It is "used up" at the rate of 14k miles per year, so the time it takes to do that is 71.5/14 ≈ 5.1 years.

Each year the car depreciates 15%. That is, its value is multiplied by 1 -15% = 0.85. In 5.1 years, the original value will be multiplied by 0.85^5.1. (Remember, exponentiation is repeated multiplication.)
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② The complement of an<br> angle. is 10 more<br> than 3 times the<br> angle. Find both
Mrac [35]
Let x be the angle. The complement is 3x + 10. The sum of two complementary angles is 90. So,
x + 3x + 10 = 90
4x + 10 = 90
4x = 80
x = 20
Plug x into the complement
3(20) + 10 = 70

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4 0
3 years ago
How is this solved using trig identities (sum/difference)?
GenaCL600 [577]
FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

cos \beta = -\frac{1}{2}  \sqrt{3}

tan \beta= \frac{1}{3}  \sqrt{3}

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2}  \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )
sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )
sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )
cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )
cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )

Find tan (α - β)
tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha  tan \beta }
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}

Simplify the denominator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5\sqrt{3}}{24})}
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the numerator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }
tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the fraction
tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})
tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}

7 0
3 years ago
Which is The graph of f(x) = 5(2)^x
Snezhnost [94]
The graph reflecting the mathematical equation f(x) = 5*2^x is attached on this answer. Graph shows the exponential manner with the y-intercept is at y = 5. we can plot this graph by substituting points of x from a certain range (positive and negative) and get their corresponding y's

5 0
3 years ago
Read 2 more answers
Find the sum and express it in simplest form. (ab+4a-6)+(ab+6)
riadik2000 [5.3K]
= 2ab + 4a + 6 - 6

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3 0
4 years ago
Read 2 more answers
Plz answer!! thanks
jeka94

Answer:

x = 10

y = 40

Step-by-step explanation:

60° + (2x + 7y)° = 180° because these two angles are supplementary

So 2x + y would be equal to 60°

60° + (2x + 7y)° = 180° subtract 60 from both sides

2x + 7y = 120 and

2x + y = 60 multiply second equation by -1 and it will be -2x -y = -60 now add it to first equation

2x + 7y -2x - y = 120 - 60 -2x will eliminate 2x

6y = 60 divide both sides by 6

x = 10

if 2x + y = 60 the we need to replace x with the value we found

2×10 + y = 60

y = 40

4 0
3 years ago
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