2 consecutive odd integers : x and x + 2
x(x + 2) = 27 + 6(x + x + 2)
x^2 + 2x = 27 + 6(2x + 2)
x^2 + 2x = 27 + 12x + 12
x^2 + 2x - 12x - 12 - 27 = 0
x^2 -10x - 39 = 0
(x + 3)(x - 13) = 0
x + 3 = 0
x = -3 (extraneous solution)
x - 13 = 0
x = 13
x + 2 = 15
so ur 2 integers are 13 and 15, with 15 being the largest
The area of one face would he h^2.
There are 6 faces, so the total surface area would be h^2 x 6
Replace total surface area with 2.16, so you now have:
2.16 = h^2 x 6
Now we can solve for h.
Divide both sides by 6:
h^2 = 2.16/6
Take the square root of both sides:
h = √2.16/6
The answer is A.
4×10^6 you subract the exponents when dividing and divide the number multiplying the 10
Here, 3x + 2y = 12
2x + 2y = 10
Subtract 2nd from 1st equation,
x = 2
Now, substitute in 2nd,
2(2) + 2y = 10
2y = 10 - 4
y = 6/2
y = 3
In short, Your Answer would be: (2, 3)
Hope this helps!
I would do this by first listing the multiples of 6 until I start to see a pattern with the one's digit.
6x0=0
6x1=6
6x2=12
6x3=18
6x4=24
6x5=30
6x6=36
6x7=42
6x8=48
...
The digits in bold are the one's digits so those are the only ones we really care about. If you list just them it looks like: 0,6,2,8,4,0,6,2,8
Notice how the first set of 5 numbers seems as though it repeats in the 6th, 7th, and 8th numbers. This probably means the pattern continues infinitely so the first 5 numbers are all the one's digits that can come from multiples of 6. Thus your answer is: 0,6,2,8,or 4
