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Mashcka [7]
3 years ago
12

A spinner contains four sections: red, blue, green, and yellow. Joaquin spins the spinner twice. The set of outcomes is given as

S = {RB, RG, RY, RR, BR, BG, BY, BB, GR, GB, GY, GG, YR, YB, YG, YY}. If the random variable is “yellow (Y),” which of the following is the correct probability distribution? A 2-column table has 3 rows. The first column is labeled Yellow: x with entries 0, 1, 2. The second column is labeled Probability with entries 0.5625, 0.375, 0.0625. A 2-column table has 3 rows. The first column is labeled Yellow: x with entries 0, 1, 2. The second column is labeled Probability with entries 0.75, 0.25, 0. A 2-column table has 3 rows. The first column is labeled Yellow: x with entries 0, 1, 2. The second column is labeled Probability with entries 0.5, 0.375, 0.125. A 2-column table has 3 rows. The first column is labeled Yellow: x with entries 0, 1, 2. The second column is labeled Probability with entries 0.5, 0.25, 0.25.
Mathematics
2 answers:
Masja [62]3 years ago
8 0

Answer:

A.

Step-by-step explanation:

Got it right edge 2021

icang [17]3 years ago
4 0

Answer:

The first table is correct

Step-by-step explanation:

x=Yellow   Prob

0               .5625

1                .375

2               .0625

The attached document shows a tree diagram with all 16 outcomes.  Each outcome has probability 1/16.

The numbers at the right show the numbe of yellows for each outcome.  There are 9 outcomes with 0 yellow (prob = 9/16).

There are 6 outcomes with 1 yellow (prob = 6/16)

There is 1 outcome with 2 yellow (prob = 1/16)

Sorry about the watermarks--distracting!

Download pdf
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20=v+9-16 <br><br><br>20=v+9+ ( )<br><br><br>20=v-<br><br><br> =v
DIA [1.3K]

Answer:

v = 27

Step-by-step explanation:

20 = v + 9 - 16

20 = v + (9 - 16)

20 = v - 7

v = 27

4 0
2 years ago
Can somone help? ill give brainlist
ale4655 [162]

Answer:

13.99+.75+.75=15.49

Part A ) 15.49

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Step-by-step explanation:

6 0
2 years ago
Which is the graph of the linear inequality y &lt; 3x + 1?<br> 3<br> 1<br> 3<br> 4.<br> 5
Arlecino [84]

Answer:

Image below

Step-by-step explanation:

<em>Hey there!</em>

<em />

Well lets graph the given inequality,

y < 3x + 1

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6 0
3 years ago
Please I need help with differential equation. Thank you
Inga [223]

1. I suppose the ODE is supposed to be

\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)

Solving for \dfrac{\mathrm dy}{\mathrm dt} gives

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}

which is undefined when t=\pm1. The interval of validity depends on what your initial value is. In this case, it's t=-\dfrac12, so the largest interval on which a solution can exist is -1\le t\le1.

2. Separating the variables gives

\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}

Integrate both sides. On the left, we have

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}

where we substituted z=y^{1/2} - or z^2=y - and 2z\,\mathrm dz=\mathrm dy - or \mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}.

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)

On the right, we have

\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)

\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C

So

2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C

\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C

y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}

y^{1/2}=C(1-t^2)^{1/4}-1

I'll leave the solution in this form for now to make solving for C easier. Given that y\left(-\dfrac12\right)=1, we get

1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1

2=C\left(\dfrac54\right)^{1/4}

C=2\left(\dfrac45\right)^{1/4}

and so our solution is

\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}

3 0
3 years ago
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lara31 [8.8K]
To get the answer we have to tranform into y=ax+b form
-2x+4y=68          /+2x
4y=2x+68          /:4
y=\frac{1}{2} x+17  - its the result

13x+4y=284           /-13x
4y=-13x+284        /:4
y=- \frac{13}{4}+ 71
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8 0
3 years ago
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