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Over [174]
3 years ago
3

A host receives a frame and computes the checksum and determines that the frame is damaged. The frame is discarded. At what laye

r of the OSI model did this happen?
1. Transport2. Network3. Data Link4. Physical
Computers and Technology
1 answer:
Sav [38]3 years ago
3 0

Answer:

3. Data link layer

Explanation:

For a frame to be created in the data link layer, the frame header and trailer must be used to encapsulate the packet from the network layer. The header contains the MAC address if the destination device and the trailer has the CRC and other parameters and flags.

The CRC or cyclic redundancy check is a calculation of the frame used to check for correctness at the destination. When the frame gets to the data-link layer of the destination device, it calculates the CRC and compares the result with that of the source. If they are equal, the frame moves on, if not, it is discarded.

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What is displayed in the alert dialog box after the following code is executed? var items = 3; for (var i = 1; i <= items; i+
LenKa [72]

Answer:

The factorial of 3=6

Explanation:

Following are the description of the given question

  • This is JavaScript code .Here items are the variable that are holding the integer value "3".
  • After that there is 2 loop are iterating one is outer and one inner loop.
  • When i=1 1<=3 the condition of outer loop is true  the control moves the inner loop .
  • In the inner loop there is variable result that is initialized by 1 Now checking the condition of inner loop j=i i.e j=1 1>=1 condition of inner loop is true it executed the statement inside the inner loop  so result =1 .Now we increment the value of i of the outer loop.
  • i=2 2<=3 the condition of outer loop is true  the control moves the inner loop .
  • In the inner loop there is variable result that is initialized by 1 Now checking the condition of inner loop j=i i.e j=2 2>=1 condition of inner loop is true it executed the statement inside the inner loop  so result =2 .Now we increment the value of i of the outer loop.
  • Now i=3 3<=3 the condition of outer loop is true  the control moves the inner loop .
  • In the inner loop there is variable result that is initialized by 1 Now checking the condition of inner loop j=i i.e j=3 3>=1 condition of inner loop is true it executed the statement inside the inner loop  so result =6 .Now we increment the value of i of the outer loop.
  • i=4 4<=3 the condition of outer loop is false  the control moves from  the outer loop.
  • It print The factorial of 3=6

4 0
3 years ago
What provision of the Government Paperwork Elimination Act was designed to encourage a paperless society?
Liula [17]
<span>The answer would be "Validation of electronic signatures"</span>
3 0
3 years ago
Read 2 more answers
Realiza un algoritmo que calcule la edad de una persona y si es mayor = a 18 que imprima mayor de edad de lo contrario que impri
WINSTONCH [101]

Answer:

Explanation:

El siguiente codigo esta escrito en Java. Le pide al usario que marque la edad. Despues el programa analiza la edad y imprime a la pantalla si el usario es mayor de edad o menor de edad. El programa fue probado y el output se puede ver en la imagen abajo.

import java.util.Scanner;

class Brainly

{

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Cual es tu edad?");

       int age = in.nextInt();

       if (age > 18) {

           System.out.println("Mayor de Edad");

       } else {

           System.out.println("Menor de Edad");

       }

   }

}

7 0
3 years ago
How to make a website
hjlf

Answer:

You need an email and a job and to be over 18 for business ones or a legal gaurdian if you have none then ur hecced uwu :333

8 0
3 years ago
Read 2 more answers
ask user to input a string. (assume length of input string is 1) If the string is lower case, print its upper case If the string
Helga [31]

Answer:

import java.util.*;

import java.util.Scanner;

class Main

{

public static void main(String[] args) {

System.out.println("Enter String");

Scanner sc1=new Scanner(System.in);

String s1= sc1.nextLine();

boolean b= isNumerc(s1);

if (b== true)

{

    System.out.println("Its number: Sorry");

}

else

{

boolean a=isStringUpperCas(s1);

if(a == false)

{

    System.out.println(s1.toUpperCase());

}

else

{

    System.out.println(s1.toLowerCase());

}

}

}

private static boolean isStringUpperCas(String st1){

     

     

      char[] arr = st1.toCharArray();

     

      int k =0; boolean flag=true;

      while(k<arr.length)

      {

         

          if( Character.isUpperCase( arr[k] ))

          {

              flag=true;

              k++;

          }

          else

          {

              flag=false;

              k++;

          }

         

      }

      return flag;

}

             

  public static boolean isNumerc(final String st1) {

     

      if (st1 == null || st1.length() == 0) {

          return false;

      }

      for (char ch : st1.toCharArray()) {

          if (!Character.isDigit(ch)) {

              return false;

          }

      }

      return true;

  }

 

}

Explanation:

Please find the program above.

8 0
3 years ago
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