Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Step-by-step explanation:
I am not sure bout this question sry
you reap what you sow ;)
Answer:
$25.25-lasagna, $12.25-garlic bread
Step-by-step explanation:
5L+3G=163
- 4L+4G=150
______________
4(5L+3G=163)
-5(4L+4G=150)
_____________
20L+12G=652
-20L-20G=-750
_____________
-8G=-98
-8G/-8 = -98/-8
G=$12.25
now plug that into G in any of the 2 equations at the top and you can solve for L(price of lasagna)