Answer:
StartFraction 16 over negative 3, EndFraction StartFraction negative 16 over 3, and EndFraction Negative (StartFraction 16 over 3 EndFraction)
I hope this helps
Step-by-step explanation:
The answer to this is credit.<span />
Answer:
Step-by-step explanation:
hope this helps
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Answer:
i don't know sorry
Step-by-step explanation:
At the end of the zeroth year, the population is 200.
At the end of the first year, the population is 200(0.96)¹
At the end of the second year, the population is 200(0.96)²
We can generalise this to become at the end of the nth year as 200(0.96)ⁿ
Now, we need to know when the population will be less than 170.
So, 170 ≤ 200(0.96)ⁿ
170/200 ≤ 0.96ⁿ
17/20 ≤ 0.96ⁿ
Let 17/20 = 0.96ⁿ, first.
log_0.96(17/2) = n
n = ln(17/20)/ln(0.96)
n will be the 4th year, as after the third year, the population reaches ≈176
