Answer:
5 times as many should be your answer.
Answer:
harvard
Step-by-step explanation:
they are really nice and smart circles
Problem 4
a)
MR = AG is a true statement because MARG is an isosceles trapezoid. The diagonals of any isosceles trapezoid are always the same length.
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b)
MA = GR is false. Parallel sides in a trapezoid are never congruent (otherwise you'll have a parallelogram).
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c)
MR and AG do NOT bisect each other. The diagonals bisect each other only if you had a parallelogram.
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Problem 5
a)
LC = AJ (nonparallel sides of isosceles trapezoid are always the same length)
x^2 = 25
x = sqrt(25)
<h3>x = 5</h3>
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b)
LU = 25
UC = 25 because point U cuts LC in half
LC = LU+UC = 25+25 = 50
AJ = LC = 50 (nonparallel sides of isosceles trapezoid are always the same length)
AS = (1/2)*AJ
AS = (1/2)*50
<h3>AS = 25</h3>
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c)
angle LCA = 71
angle CAJ = 71 (base angles of isosceles trapezoid are always congruent)
(angleAJL)+(angleCAJ) = 180
(angleAJL)+(71) = 180
angle AJL = 180-71
<h3>angle AJL = 109 </h3>
Answer:
Step-by-step explanation:
Whether we divide using long division or using synthetic division, the rule is the same: If, after division, there is no remainder (i. e., the remainder is zero), the divisor binomial is a factor or the associated root is indeed a root/zero/solution.
Divide 5x³+8x²-7x-6 by (x+2) using synthetic division. Use the divisor -2 (which comes from letting x+2 = 0):
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-2 / 5 8 -7 -6
-10 4 6
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5 -2 -3 0 Since the remainder here is 0, we know that
-2 is a root of 5x³+8x²-7x-6 and that (x+2) is
a factor of 5x³+8x²-7x-6.
Now check out the possibility that (x+1) is a factor of 5x^3 + 8x^2 - 7x - 6:
Use -1 as the divisor in synthetic division:
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-1 / 5 8 -7 -6
-5 -3 10
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5 3 -10 4
Since there is a non-zero remainder (4), we can conclude that (x + 1) is NOT a factor of the given polynomial expression.
Answer:
11
Step-by-step explanation: