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Ratling [72]
3 years ago
10

Gas prices are up 30% since last year when they were $4.35, how much is gas now?

Mathematics
1 answer:
rosijanka [135]3 years ago
5 0

Answer:

given;

previous year price of gas= $4.35

price of gas has been increased by 30%

now,price of gas in present year=?

we have;

price of gas in present year=priceof

previous year+30%of price of previous year.

so ,price of gas in present year=4.35+30%of4.35

=$4.35+30/100×4.35

=$4.35+1.305

= $5.655. ans....

therefore, the price of gas in present year is ;$5.655.

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Answer:

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Step-by-step explanation:

12-n/7 = -1

Cross multiply

We have 12-n = -7

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12 + 7 = n

Therefore n = 19

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drek231 [11]

Answer:

\huge\boxed{p(x)=4x^3-20x^2+4x+300}

Step-by-step explanation:

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p(x)=(x^2-2(x)(4)+4^2-3^2i^2)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ i^2=-1\\\\p(x)=(x^2-8x+16-9(-1))(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+16+9)(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+25)(x+3)\bigg(r(x)\bigg)\qquad\text{use FOIL}:\ (a+b)(c+d)=ac+ad+bc+bd\\\\p(x)=\bigg((x^2)(x)+(x^2)(3)+(-8x)(x)+(-8x)(3)+(25)(x)+(25)(3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x^3+3x^2-8x^2-24x+25x+75)\bigg(r(x)\bigg)\qquad\text{combine like terms}\\\\p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)

\text{The y-intercept is at 300}.\\\\\text{For}\ w(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+...+a_1x+a_0\\\\\text{y-intercept is}\ a_0\\\\\text{Therefore for}\ p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)\\\\\text{y-intercet is}\ 75\bigg(r(x)\bigg)\\\\75\bigg(r(x)\bigg)=300\qquad\text{divide both sides by 75}\\\\r(x)=4\\\\\text{Finally:}\\\\p(x)=(x^3-5x^2+x+75)(4)\qquad\text{use the distributive property}\\\\p(x)=(x^3)(4)+(-5x^2)(4)+(x)(4)+(75)(4)\\\\p(x)=4x^3-20x^2+4x+300

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Answer:

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Step-by-step explanation:

We are given:

g(x) =10x +2

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10x+2=2

Now, we need to solve for x. First, move all the numbers to the same side. Subtract 2 from both sides

10x+2-2=2-2

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To solve for x, we have to get x by itself. x and 10 are being multiplied. To get x alone, divide both sides by 10.

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