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Eva8 [605]
2 years ago
14

The cost of two tables and three chairs is 705$. If the table costs 40$ more than the chair, find the cost of one table and two

chairs
Mathematics
1 answer:
DaniilM [7]2 years ago
6 0

it the cost of the table is 40 more than the chairs than one chair is 166.25 and the table is 206.25 so one table plus two chairs is 538.75 and how is you take the total subtract the 40 extra for the table then divide by 4 because of three chairs and the table then take that amount (the price of one chair) and add 40 to get the cost of the table then take the cost of the chair, double it, then add the table to get the total of $538.75


hope that helps brainlyest pls?

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Sensitivity = 66.7%  (C)

specificity= 98.0%  (E)

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Step-by-step explanation:

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Test Positive                      24                                        6                        30

Test Negative                    12                                       288                     300

Total                                   36                                       294                    330

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specificity= [D/(D+B)]×100 = [288/(288+6)]×100 = [288/294]×100

specificity= 98.0%  (E)

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= [24/30]×100

positive predictive value = 80.0%  (F)

Negative predictive value = [D/(D+C)]×100 = [288/(288+12)]×100

= [288/300]×100

Negative predictive value = 96.0%  (D)

accuracy of the test = [A+D/(A+B+C+D)]×100 = [24+288/(24+6+12+288)]×100

= [312/330]×100

accuracy of the test  = 94.5%  (A)

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