The cost of two tables and three chairs is 705$. If the table costs 40$ more than the chair, find the cost of one table and two
1 answer:
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Answer:
Charlotte spend of day trying on jeans
Step-by-step explanation:
Charlotte spent part of day on shopping =
She spent part of shopping time on trying jeans =
We are supposed to find What fraction of the day did Charlotte spend trying on jeans.
She spent fraction of the day in trying jeans =
She spent fraction of the day in trying jeans =
Hence Charlotte spend of day trying on jeans
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
Solution:
Let f be the bags of flour and b be the pounds of butter.
Cost of 20 bags of flour 16 pound of butter = 110
⇒ 20f + 16b = 110 -------------------- (1)
Cost of 30 bags of flour 12 pound of butter = 120
⇒ 30f + 12b = 120 -------------------- (2)
Equation (1) and (2) are the system of equations.
(2) ⇒ 30f + 12b = 120
Subtract 30f from both sides.
⇒ 12b = 120 – 30f
Divide by 12 on both sides.
-------------------- (3)
Substitute (3) in (1).
Subtract 160 from both sides.
Divide by –20, we get
f = 2.50
Substitute f = 2.5 in equation (3), we get
b = 3.75
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75