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3 years ago

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Natalie sawed 5 boards of equal lenghtto make a stool. each was 9 tenths of a meter long . what is the total length if the board

s she sawed ? express your answer as the sum of a whole number and the remaining fractional units . draw a number line to represent the problem.

1 answer:

AnnyKZ [126]3 years ago

3 0

I hope I answered this correctly. Hope it helps

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What are the best approximations of the solutions to this system?

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(-1.2,-2.0) and (1.9,2.2) are the best approximations of the solutions to this system.

Option B

<u>Step-by-step explanation:</u>

Here, we have a graph of two functions from which we need to find the approximate value of common solutions. Let's find this:

First look at where we have intersection points, In first quadrant & in third quadrant.

<u>At first quadrant:</u>

Draw perpendicular lines from x-axis & y-axis from this point . After doing this we can clearly see that the perpendicular lines cut x-axis at x=1.9 and y-axis at y=2.2. So, one point is (1.9,2.2)

<u>At Third quadrant:</u>

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3 years ago

Which sequence of transformations would result in an image that is similar and non-congruent to the pre-image? Assume that any s

Fofino [41]

Answer:

a, b, c, and e.

Step-by-step explanation:

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3 years ago

Which is an equation for the line shown?<br> A) x=2<br> B) y=2<br> C) x=-2<br> D) y=-2

Studentka2010 [4]

Answer:

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2 years ago

1.) Find the value of the discriminant and the the number of real solutions of

ruslelena [56]

Hi there!

When we have an equation standard form...
$a {x}^{2} + bx + c = 0$
...the formula of the discriminant is
D = b^2 - 4ac

When
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D = 0 we have one real solutions
D < 0 we don't have real solutions

1.) Find the value of the discriminant and the the number of real solutions of
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Plug in the values from the equation into the formula of the discriminant

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Again, plug in the values from the equation into the formula of the discriminant.

${4}^{2} - 4 \times 2 \times 2 = 16 - 16 = 0$

D = 0 and therefore we have one real solution.

~ Hope this helps you.

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QveST [7]

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