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3 years ago

What equal z=? I'm to confused she didn't tell us how to do it

Mathematics

1 answer:

AleksandrR [38]3 years ago

7 0

First add 19 over so that you are left with z/4 by itself. Then to get z by itself multiply both sides by 4.

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Can someone pls answer them all?

nirvana33 [79]

If you multiply by 24 you should get $864

3 0

2 years ago

Read 2 more answers

The following data points represent the number of animal crackers in each kid's lunch box.

OLga [1]

Answer:

IQR = 7

Step-by-step explanation:

To get the interquartile range of the set of data, the following steps must be followed:

Datas 4, 4, 6 , 7, 10 , 11 , 12, 14 ,15

Step 1: Rearrange the datas in ascending or descending order if not arranged.

4, 4, 6 7, 10, 11, 12, 14, 15

Step 2:

We will locate the (N+1/4)the cumulative value of the data where N is the total frequency of the data.

N = 4 + 4 + 6 + 7 + 10 + 11 + 12 + 14 + 15

N = 83

N+1/4 = 83+1/4

= 84/4

= 21st cumulative value

On cumulating the values up to the 21st value or more:

4 + 4 + 6 + 7

= 21

Since the 21st value falls on 7, then the interquartile range of the set of data is 7

3 0

3 years ago

Read 2 more answers

Assume that T is a linear transformation. Find the standard matrix of T. T: R^3 right arrow R^2 , T(e 1) =(1,2), and T(e2 ) =( -

irina [24]

Answer:

$A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]$

Step-by-step explanation:

Given

$T:R^3->R^2$

$T(e_1) = (1,2)$

$T(e_2) = (-4,6)$

$T(e_3) = (2,-6)$

Required

Find the standard matrix

The standard matrix (A) is given by

$Ax = T(x)$

Where

$T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]$

$Ax = T(x)$ becomes

$Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]$

The x on both sides cancel out; and, we're left with:

$A = [T(e_1)\ T(e_2)\ T(e_3)]$

Recall that:

$T(e_1) = (1,2)$

$T(e_2) = (-4,6)$

$T(e_3) = (2,-6)$

In matrix:

$(a,b)$ is represented as: $\left[\begin{array}{c}a\\b\end{array}\right]$

So:

$T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]$

$T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]$

$T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]$

Substitute the above expressions in $A = [T(e_1)\ T(e_2)\ T(e_3)]$

$A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]$

Hence, the standard of the matrix A is:

$A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]$

6 0

3 years ago

14.7 ml and a mass of 22.8 g

aliya0001 [1]

The density of the liquid is 1.55 g/mL.

Given the following data:

Mass of liquid = 22.8 grams

Volume of liquid = 14.7 mL

To find the density (unknown) of the liquid:

Density is mass all over the volume of a substance or an object. Thus, density is mass per unit volume of an object.

Mathematically, the density of a substance is given by the formula;

Substituting the values into the formula, we have;

Density = 1.55 g/mL

Therefore, the density of the liquid is 1.55 g/mL.

Read more: brainly.com/question/18320053

5 0

1 year ago

When making a long distance call from a certain pay phone, the first three minutes of a call cost $2.10. After that, each additi

Sauron [17]

Answer: the number of minutes of long distance call that one can make is lesser than or equal to 12 minutes.

Step-by-step explanation:

Let x represent the number of minutes of long distance call that one makes.

The first three minutes of a call cost $2.10. After that, each additional minute or portion of a minute of that call cost $0.45. This means that if x minutes of long distance call is made, the total cost would be

2.10 + 0.45(x - 3)

Therefore, the inequality to find the number of minutes one can call long distance for $6.15 is expressed as

2.10 + 0.45(x - 3) ≤ 6.15

2.10 + 0.45x - 1.35 ≤ 6.15

0.75 + 0.45x ≤ 6.15

0.45x ≤ 6.15 - 0.75

0.45x ≤ 5.4

x ≤ 5.4/0.45

x ≤ 12

4 0

3 years ago