Compose the quadratic condition in standard shape, ax2 + bx + c = 0. Recognize the values of a, b, c. Write the Quadratic Equation. At that point substitute within the values of a, b, c. Simplify. Check the arrangements.
We have

Plug in

:

⇒

So we now have

Plug in

:

⇒

⇒
![b=\sqrt[3]{\frac{95}{4}}](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B95%7D%7B4%7D%7D)
which is approximately 2.874
So we get
![y=4(\sqrt[3]{\frac{95}{4}})^{x}](https://tex.z-dn.net/?f=y%3D4%28%5Csqrt%5B3%5D%7B%5Cfrac%7B95%7D%7B4%7D%7D%29%5E%7Bx%7D)
or, in decimal form,
So you need to divide 430 into 25 to get 17.2
So he/she earns $17.20 an hour or in word format :seventeen dollars and twenty cents and hour
(3,-6) that’s the answer but my teacher showed me this, how far away is 3 from 3? Well it’s the same so no distance so it stays the same , how far away is 2 away from 8? It would be 6. Home this helps