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4 years ago

Hey metalanimelover, ive heard people say apex is like being in a dream

Mathematics

1 answer:

Ksivusya [100]4 years ago

6 0

Answer:

i was on the homepage and i was scrolling and then i saw a glimpse of my user and im like WAIT WHAT XD

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A drama class has a total of 39 students. The number of males is 9 more than the number of females. How many males and how many

Artist 52 [7]

Answer:

Step-by-step explanation:M+F=39

M+F=39

F=M-9

Substitute

M + M - 9 = 39

2M = 48

M=48/2

M=24

24+F=39

F=39-24=15

F=15, M=24

3 0

3 years ago

Read 2 more answers

11/28+4/7 = simplest form

MatroZZZ [7]

The answer to this question is 27/28

4 0

3 years ago

At a school number of boys: number of girls= 11:9

vredina [299]

составим уравнение
11х=9х+124
2х=124
х=62

проверим ответ
682=558+124

тогда, общее количество детей

682+558=1240

4 0

2 years ago

A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr

worty [1.4K]

Answer: The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation: Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8 and n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.$

Now, the probability of pulling three green marbles out with replacement is given by

$P(G)\times P(G)\times P(G)=\dfrac{5}{25}\times\dfrac{5}{25}\times \dfrac{5}{25}=\dfrac{1}{125}=\dfrac{1}{125}\times100\%=0.8\%.$

Thus, the probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

4 0

3 years ago

Can someone explain to me why are we adding 2kpi when we are doing zeros for sin and cos, but adding kpi when doing zeros for tg

makvit [3.9K]

on the first exercise, you got a solution angle of π/18, that's a good solution for the I Quadrant only, however, on a circle, we have angles that go from 0 to 2π, however we can always keep on going around and continute to 2π + π/2 or 3π or 4π, or 115π/3 or 1,000,000π/18 and so on, and we're really just going around the circle many times over, getting a larger and larger angle, same circular motion.

π/18 on that exercise works for the I Quadrant, however if we continue and go around say 2π, we'll find that 2π/3 + π/18 is a coterminal angle with π/18, and thus that angle has also the same sine value.

π/18 + 2kπ/3 , where k = integer, is a way to say, all angles around the circle that look like this have the same sine, namely

π/18 + 2(1)π/3

π/18 + 2(2)π/3

π/18 + 2(3)π/3

π/18 + 2(5)π/3

π/18 + 2(99999999)π/3

.....

so using the "k" as some sequence multiplier, is a generic notational way to say, "all these angles".

you'll also find that "n" is used as well for the same notation, say for example

2π/3 + 2πn.

8 0

3 years ago