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2 years ago

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What is the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)? x=

–y216+6y16–4116 y= –x216+6x16–4116 y=x216–6x16+4116 x=y216–6y16+4116

1 answer:

Genrish500 [490]2 years ago

5 0

Answer:

y=x216–6x16+4116

Step-by-step explanation:

plato :)

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What is the sum of 6 feet 10 inches and 8 feet 9 inches

slega [8]

6 ft 10 in + 8 ft 9 in = 15 ft 7 in

add the inches first and then subtract 12 from the 19 because 12 inches equals 1 foot then add 6+8+1=15 ft don't forget to include the 7 inches in your answer

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2 years ago

Given f(x)=2(3)x what f (2)?

Drupady [299]

Answer:

$f(2)=18$

Step-by-step explanation:

Assuming the "x" to be an exponent:

$f(x)=2(3)^x$

$f(2)=2(3)^2$

$f(2)=2(9)$

$f(2)=18$

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1 year ago

What is the equation in standard form of the line that passes through the point (-7, 2) and has a

Orlov [11]

Answer:

y=3x+23 (lmk if you need me to explain)

Step-by-step explanation:

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2 years ago

The mean distance of the Moon from Earth is 2.39x10^5 miles. Assuming that the orbit of the Moon around Earth is circular and th

olya-2409 [2.1K]

Answer:

2291,94 mph

Step-by-step explanation:

To solve this we need to consider the distance 2.39x10^5 miles as the distance between the center of the earth and the center of the moon, if not we would need to know the radius of the earth and the moon.

If the distance is 2.39x10^5 miles, the orbit is = 2.Pi.(2.39x10^5) miles=1501681.288miles

It takes 27.3 days, that are, 27.3*24= 655.2hours

1501681.288miles/655.2hours= 2291.94 mph

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2 years ago

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

2 years ago