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Butoxors [25]
4 years ago
11

Which of the following correlation coefficients would correspond to a strong linear relationship in a data set? a. 0 b. 7 c. 0.9

d. 0.4
Mathematics
1 answer:
ahrayia [7]4 years ago
5 0
<h3>Answer: c) 0.9</h3>

The correlation coefficient r is always between -1 and 1, inclusive of both endpoints. We can write -1 \le r \le 1

If r = 0, then we have no linear correlation at all. If r = 1, then we have perfect positive correlation. If r = -1, then we have perfect negative correlation.

We see that r = 0.9 is close to r = 1, so we have strong positive linear correlation going on here.

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How do I do this I really need to know!
Nostrana [21]

Answer:

Step-by-step explanation:

I'm doing seven.

<em><u>x = -2</u></em>

y = 2^(-2 -1) + 2

y = 2^(-3) + 2

y = 1/2^3 + 2

y = 1/8 + 2

y = 2.125 which is a guess on the graph.

<em><u>x = - 1</u></em>

y = (2)^(-1 -1) + 2

y = (2)^-2 + 2

y = 1/4 + 2

y = 2.25

x = 0

y = 2^(0 - 1) + 2

y = 2^(-1) + 2

y = 1/2 + 2

y = 2.5

<em><u>x = 1</u></em>

y = 2^(1 - 1) + 2

y = 2^0 + 2           If the power of a number = 0 then the result = 1. The only exception to that is 0^0

y = 1 + 2

y = 3

Eight

<em><u>x = -1</u></em>

y = (1/2)^(-1 + 1) + 2

y = 1 + 2

y = 3

<em><u>x = 0</u></em>

y = (1/2)^(0 - 1) + 2

y = (1/2)^-1 + 2             Turn the 1/2 upside down

y = 2 + 2

y = 4

<em><u>x = 1</u></em>

y = (1/2)^(1 + 1) + 2

y = (1/2)^2 + 2

y = 1/4 + 2

y = 2.25

<em><u>x = 2</u></em>

y = (1/2)^(2 + 1) + 2

y = (1/2)^3 + 2

y = 1/8 + 2

y = 2.125

6 0
4 years ago
Solve <br> x=4y+2<br> x+y-2=6 by using elimination and substitution
timama [110]

Answer: The Answer is x=6,y=−1  

Step-by-step explanation:  (SUBSTITUTION) x=4y+2x+−2=6

Consider the first equation. Subtract 4y from both sides.

x−4y=2x−2

Subtract 2x from both sides.

x−4y−2x=−2

Combine x and −2x to get −x.

−x−4y=−2

Consider the second equation. Add 2 to both sides.

4y+2x=6+2

Add 6 and 2 to get 8.

4y+2x=8

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

−x−4y=−2,2x+4y=8

Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.

−x−4y=−2

Add 4y to both sides of the equation.

−x=4y−2

Divide both sides by −1.

x=−(4y−2)

Multiply −1 times 4y−2.

x=−4y+2

Substitute −4y+2 for x in the other equation, 2x+4y=8.

2(−4y+2)+4y=8

Multiply 2 times −4y+2.

−8y+4+4y=8

Add −8y to 4y.

−4y+4=8

Subtract 4 from both sides of the equation.

−4y=4

Divide both sides by −4.

y=−1

Substitute −1 for y in x=−4y+2. Because the resulting equation contains only one variable, you can solve for x directly.

x=−4(−1)+2

Multiply −4 times −1.

x=4+2

Add 2 to 4.

x=6

System now finished.

x=6,y=−1

STEPS USING ELIMINATION

x=4y+2x+−2=6

Consider the first equation. Subtract 4y from both sides.

x−4y=2x−2

Subtract 2x from both sides.

x−4y−2x=−2

Combine x and −2x to get −x.

−x−4y=−2

Consider the second equation. Add 2 to both sides.

4y+2x=6+2

Add 6 and 2 to get 8.

4y+2x=8

In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

−x−4y=−2,2x+4y=8

To make −x and 2x equal, multiply all terms on each side of the first equation by 2 and all terms on each side of the second by −1.

2(−1)x+2(−4)y=2(−2),−2x−4y=−8

Simplify.

−2x−8y=−4,−2x−4y=−8

Subtract −2x−4y=−8 from −2x−8y=−4 by subtracting like terms on each side of the equal sign.

−2x+2x−8y+4y=−4+8

Add −2x to 2x. Terms −2x and 2x cancel out, leaving an equation with only one variable that can be solved.

−8y+4y=−4+8

Add −8y to 4y.

−4y=−4+8

Add −4 to 8.

−4y=4

Divide both sides by −4.

y=−1

Substitute −1 for y in 2x+4y=8. Because the resulting equation contains only one variable, you can solve for x directly.

2x+4(−1)=8

Multiply 4 times −1.

2x−4=8

Add 4 to both sides of the equation.

2x=12

Divide both sides by 2.

x=6

The system is now solved.

x=6,y=−1

7 0
2 years ago
What is 5y+=33u<br> this is not an answer
marishachu [46]

Answer:

y = 33u/5

u = 5y/33

7 0
3 years ago
On a coordinate plane, a line goes through points (0, 0) and (1, 3).
gtnhenbr [62]

Answer:

3 on edge

Step-by-step explanation:

Just did the assignment

5 0
3 years ago
Which graph best represents the solution to the system of equations shown below?
goldfiish [28.3K]

First find the x and y values because where the lines will intersect, they share the point of the intersection so they will share the x and y coordinates.

Rearrange equations

4x + y = 19

- 2x + y = 1

To cancel y, we must do equation 1 minus equation 2. Similarly:

4x -  - 2x = 4x + 2x = 6x

19 - 1 = 18

6x = 18

x = 18 \div 6 = 3

So the x coordinate is 3.

The y coordinate can be found with substitution of x into one of the equations:

y = 2x + 1 = 2(3) + 1 = 7

So where the two lines intersect is at the point (3, 7), which is the solution to the equations.

4 0
3 years ago
Read 2 more answers
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