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vazorg [7]
3 years ago
9

How do you solve g/9+47=64. What do you get for g

Mathematics
1 answer:
meriva3 years ago
5 0
G/9+47=64
first you would subtract 47 from each side getting g/9=17 then you would x9 on each side getting g=153

g=153

then to check plug in 153 for g
153/9+4=?
64
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Toni simplified the expression , 22 × (16 −32 +1) ÷ 8. For Toni's first and second steps, he simplified the expression inside th
Anna007 [38]
When you subtract and add what is in the parentheses you would get -15 so I’m guessing he didn’t go from left to right when working inside the parentheses but when you solve the whole problem out you would get the answer: -41.25 If I missed something or you need me to show the work just let me know but I hope this helps !
6 0
2 years ago
The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

AV = \frac{y(t2) - y(t1)}{t2 - t1}

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8

So the average speed is -128.9 ft/s

iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0
2 years ago
What is the area of a rectangle with a length of 5/8foot and a width of 4/9 foot?
VLD [36.1K]
The answer is 20/72 or 5/18
5 0
2 years ago
19)
lesantik [10]
It would be answer D your welcome
3 0
2 years ago
Read 2 more answers
I need the correct answer and explanation
Arada [10]

Answer:

D - The elevator traveled upward at a rate of 2(2/5) feet per second.

Step-by-step explanation:

Okay, this is almost like kinematics, which deals with physics.

Here are your given values:

Position 1 = 70ft [down]

Position 2 = 10ft [down]

Change in time (Δt - time - scalar) = 25 seconds

The equation for displacement is d₂-d₁. This would be the change of position of the elevator during the 25 seconds.

So, we can use this equation to figure out the change in position.

Δd = d₂-d₁ = 10ft [down] - 70 ft [down] = 60ft [up]

The equation for velocity is Δd/Δt. This would be the rate of which the elevator travels. Velocity is simply speed but with a direction.

So, we can use this equation to solve.

v = Δd / Δt = 60 feet [up] / 25 seconds = 2.4 ft / second [up].

Now, we need to change 2.4 ft / second [up] into a fraction.

2.4 -> 2 (4/10) -> 2 (2/5)


All I am simply doing is figuring out the distance the elevator traveled and determined the direction of which the elevator traveled. Then, I divided that by the time the elevator traveled to determine its speed and the direction the elevator traveled.

4 0
3 years ago
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