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3 years ago

Carla earns $564 for 30 hours of work. Which represents the unit rate?

Mathematics

2 answers:

VLD [36.1K]3 years ago

6 0

The answer is C) $18.80 per hour

Travka [436]3 years ago

4 0

The answer is c because when you divide 564 by 30 it gives you 18.8

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7 ounce- 4.58$<br> 15 ounce- 6.30$<br> Find the unit rate of both numbers

Zielflug [23.3K]

Answer:

7 ounces-4.58 = 1 ounce-0.654....

15 ounces-6.30= 1 ounce- 0.42

Explanation:

Divide 4.58 and 7 and divide 6.30 and 15.

And you get your answers.

I think im not really good with unit rate.

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3 years ago

I need help finding the question to my answer please help

devlian [24]

Answer: What question? wdym?

Step-by-step explanation:

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3 years ago

The side of each of the equilateral triangles in the figure is twice the side of the central regular hexagon. What fraction of t

lana [24]

Answer:

The fraction is 1/4

Step-by-step explanation:

we know that

The area of an equilateral triangle, using the law of sines is equal to

$A=\frac{1}{2}x^{2}sin(60^o)$

$A=\frac{1}{2}x^{2}(\frac{\sqrt{3}}{2})$

$A=x^{2}\frac{\sqrt{3}}{4}$

where

x is the length side of the triangle

In this problem

Let

b ----> the length side of the regular hexagon

2b ---> the length side of the equilateral triangle

step 1

Find the area of the six triangles

Multiply the area of one triangle by 6

$A=6[x^{2}\frac{\sqrt{3}}{4}]$

$A=3x^{2}\frac{\sqrt{3}}{2}$

we have

$x=2b\ units$

substitute

$A=3(2b)^{2}\frac{\sqrt{3}}{2}\\\\A=6b^{2}\sqrt{3}\ units^2$

step 2

Find the area of the regular hexagon

Remember that, a regular hexagon can be divided into 6 equilateral triangles

The area of the regular hexagon is the same that the area of 6 equilateral triangles

$A=3x^{2}\frac{\sqrt{3}}{2}$

we have

$x=b\ in$

substitute

$A=3(b)^{2}\frac{\sqrt{3}}{2}$

step 3

To find out what fraction of the total area of the six triangles is the area of the hexagon, divide the area of the hexagon by the total area of the six triangles

$3(b)^{2}\frac{\sqrt{3}}{2}:6b^{2}\sqrt{3}=\frac{3}{2} :6=\frac{3}{12}=\frac{1}{4}$

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4 years ago

17. Factor x ^ 3 + 5x ^ 2 - 9x - 45 . A. (x - 5)(x ^ 2 + 9) b . (x - 5)(x - 3) * (x + 3) Factor By Groupin (x + 5)(x - 3) * (x +

jok3333 [9.3K]

Answer:

Step-by-step explanation:

Given

x³ + 5x² - 9x - 45 ( factor the first/second and third/fourth terms )

= x²(x + 5) - 9(x + 5) ← factor out (x + 5) from each term

= (x + 5)(x² - 9) ← factor as a difference of squares

= (x + 5)(x - 3)(x + 3)

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3 years ago

How do u write a expression

zhuklara [117]

Answer:

<h2><u>it depends on what expression u want </u></h2>

Step-by-step explanation:

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3 years ago

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