F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3
Answer:
69 noice
Step-by-step explanation:
Answer:
372 inches
Step-by-step explanation:
(1 yd = 36 in., and 1 ft = 12 in.)
1 yard stick = 24 in
This means , height of 36 inches casts a shadow of 24 Inches
At the same time a telephone pole casts a shadow of 20 ft 8 in
1 ft = 12 in
Hence,
Convey 20ft to inches
1 ft = 12 in
20 ft = 20 × 12 inches
= 240 inches
Total shadow of the telephone pole = 240in + 8 in = 248 = 248 inches
Hence,
Height/Length of shadow = Height/Length of shadow
36/24= x /248
Cross Multiply
24 × x = 36× 248
x = 36 × 248/24
x = 372 inches
The height of the telephone pole, to the nearest inch is 372 inches
Answer:
5% error
Step-by-step explanation:
