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Svet_ta [14]
3 years ago
11

I need help with this

Mathematics
1 answer:
ra1l [238]3 years ago
4 0

Answer:

156 degrees

Step-by-step explanation:

Bisects meand to cut into two equal halves.

That means 4x-2=3x+18.

Subtracting 3x on both sides gives x-2=18

Adding 2 on both sides gives x=20

If x=20, then 4x-2 equals 4(20)-2=78.

The other half is also 78 since the two angles were comgruent.

The whole angle is 78+78=156.

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What is the volume of this solid? Use 3.14 for pi. 37.68 cm³ 138.16 cm³ 169.56 cm³ 207.24 cm³ A solid consisting of a cone on to
yulyashka [42]
Volume of Solid = Volume of Cylinder + Volume of Cone
Volume of Cylinder = πr²h
v= 3.14 * (3)² * 6
v = 169.56

Volume of Cone = πr² h/3
v = 3.14 * (3)² * 4/3
v = 37.7

Now, V = 169.56 + 37.7 = 207.26 cm³

Hope this helps!
8 0
3 years ago
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Yˆ=2.391x+57.420 which number is the y intercept?
BaLLatris [955]

Answer:

57.420

Step-by-step explanation:

The y intercept is always the number on the out side next to the slope which is 2.391

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The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room
Alexandra [31]

Answer:

\bar x = 260.1615

\sigma = 70.69

The confidence interval of standard deviation is: 53.76 to 103.25

Step-by-step explanation:

Given

n =20

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}

\bar x = \frac{5203.23}{20}

\bar x = 260.1615

\bar x = 260.16

Solving (b): The standard deviation

This is calculated as:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}

\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}\sigma = \sqrt{\frac{94938.80}{19}}

\sigma = \sqrt{4996.78}

\sigma = 70.69 --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

c =0.95

So:

\alpha = 1 -c

\alpha = 1 -0.95

\alpha = 0.05

Calculate the degree of freedom (df)

df = n -1

df = 20 -1

df = 19

Determine the critical value at row df = 19 and columns \frac{\alpha}{2} and 1 -\frac{\alpha}{2}

So, we have:

X^2_{0.025} = 32.852 ---- at \frac{\alpha}{2}

X^2_{0.975} = 8.907 --- at 1 -\frac{\alpha}{2}

So, the confidence interval of the standard deviation is:

\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} } to \sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }

70.69 * \sqrt{\frac{20 - 1}{32.852} to 70.69 * \sqrt{\frac{20 - 1}{8.907}

70.69 * \sqrt{\frac{19}{32.852} to 70.69 * \sqrt{\frac{19}{8.907}

53.76 to 103.25

8 0
2 years ago
100 points please hurry!!
tigry1 [53]

Answer:

A. The kinetic energy is quartered.

Step-by-step explanation:

The kinetic energy is quartered.

6 0
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Are these three correct? (4,7 and 17.)
Helga [31]
Nine pairs is the answer
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