Subtract 4 from each term:
1 = 10
2 = 6
3 = 2
4 = -2
5 = -6
6 = -10
7 = -14
8 = -18
9 = -22
10 = -26
11 = -30
12 = -34
The answer is -34.
Hope this helped☺☺
Answer: Probability that two people have the same number of repeats in both location A and location B is ![\dfrac{1}{40000Step-by-step explanation:Since we have given that Probability that two people both have 3 repeat sequences at location A = [tex]\dfrac{1}{500}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B40000%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3ESince%20we%20have%20given%20that%20%3C%2Fp%3E%3Cp%3EProbability%20that%20two%20people%20both%20have%203%20repeat%20sequences%20at%20location%20A%20%3D%20%5Btex%5D%5Cdfrac%7B1%7D%7B500%7D)
Probability that two people both have 4 repeat sequences at location B = ![\dfrac{1}{800}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B800%7D)
P(A) =
and P(B) = ![\dfrac{1}{800}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B800%7D)
Since A and B are independent events.
According to question,
![P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\dfrac{1}{500}\times \dfrac{1}{800}\\\\P(A\cap B)=\dfrac{1}{40000}](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3DP%28A%29.P%28B%29%5C%5C%5C%5CP%28A%5Ccap%20B%29%3D%5Cdfrac%7B1%7D%7B500%7D%5Ctimes%20%5Cdfrac%7B1%7D%7B800%7D%5C%5C%5C%5CP%28A%5Ccap%20B%29%3D%5Cdfrac%7B1%7D%7B40000%7D)
Hence, probability that two people have the same number of repeats in both location A and location B is ![\dfrac{1}{40000}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B40000%3C%2Fstrong%3E%7D)
Answer:
sure!
Step-by-step explanation:
:)