For
c=ax+by
the slope is -a/b
given
-48=2x-8y
slope=-2/-8=-1/-4=1/4
slope=1/4
I beilieve it’s 11 I’m not 100% certain though
Answer:
y = cot(x - ⅓π) + 2
Step-by-step explanation:
The general equation for a cotangent function with the given properties is
y = Acot(Bx + C) + D, where
A = the stretching factor
π/|B| = the period
C = the phase shift (negative is to the right)
D = the vertical shift
A = 1
π/|B| = π, so1/|B| = 1 and B = 1
C = -⅓π
D = 2
The function is
y = cot(x - ⅓π) + 2
The figure below shows the graph of the function with the given parameters.
Note that the parent function y = cot(x) has the y-axis as an asymptote, so we can measure the phase shift by the movement of the asymptote π units to the right.
Answer:
Angle A: 72°
Angle B: 108°
Step-by-step explanation:
Opposite angles are equal
Adjacent angles add up to 180
5y - 3 = 3y + 27
2y = 30
y = 15
Angle A:
5(15) - 3 = 72°
Angle B:
180 - 72 = 108°