Explain the difference between a simple random sample and a systematic sample.

Mathematics

1 answer:

Stells [14]3 years ago

5 0

Answer:

Step-by-step explanation:

Simple random sampling otherwise called probability sampling involves selecting a subset of a part of a population in which each member of the population has equal chances of being selected while systematic sampling involves the use of sampling interval which is determined by dividing the population by the sample size and a random starting point is selected. for example let say we have a population of 1000 people and we want to systematically select 50 people, 1000 / 50 = 20, it means after choosing a random starting point, we select every 20th person after the starting point until the desire sample size has been attained.

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2. The student council is sponsoring a concert as

Jlenok [28]

Answer:

80 adults must addent to make a complete $1,000

Step-by-step explanation:

You start with the students, $3 for each and 200 of them attend. 3x200=600 dollars in total. Then you would subtract 600 from 1,000. Next you will do the adults, 5x80=400 (The "leftover" cash) $5 for each times 80 adults will be $400 in total.

8 0

3 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$

3 0

2 years ago

Read 2 more answers

A cone and a triangular pyramid have a height of 9.3 m

Otrada [13]

Answer:

$x=17.1\ in$

Step-by-step explanation:

<u><em>The complete question is</em></u>

A cone and a triangular pyramid have a height of 9.3 m and their cross-sectional areas are equal at every level parallel to their respective bases. The radius of the base of the cone is 3 in and the other leg (not x) of the triangle base of the triangular pyramid is 3.3 in

What is the height, x, of the triangle base of the pyramid? Round to the nearest tenth

The picture of the question in the attached figure

we know that

If their cross-sectional areas are equal at every level parallel to their respective bases and the height is the same, then their volumes are equal

Equate the volume of the cone and the volume of the triangular pyramid

$\frac{1}{3}\pi r^{2}H=\frac{1}{3}[\frac{1}{2}(b)(h)H]$