This is just a cylinder, with a cone and half of a sphere carved out of it.
Just find the volume of the cylinder, then subtract the volume of the cone and the volume of the half-sphere from it, and you'll have the volume of the part that's left.
Now I'll tell you why this problem was assigned: The purpose is
to give you an opportunity to recall the formulas for the volumes
of these three shapes. To hep you recall them, here they are:
Volume of a cylinder = (pi) (radius of the round end)² (length)
Volume of a cone= (1/3) (pi) (radius of the round end)²
Volume of a whole sphere= (4/3) (pi) (radius of the whole sphere)³
Notice that in the weird contraption in the picture, the cylinder,
the cone, and the half-sphere all have the same radius.
The answer is p=w/6
explanation:
6=w/p
6p=w (multiply both sides by p to get rid of the fraction)
p=w/6 (divide by 6 on both sides to get p by itself)
Un tercio ,,,,.........,,.
(3^2)^-2
9
9^-2 = 1/9^2 ---> 1/81
should be 1/81