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nasty-shy [4]
3 years ago
5

Please can you help me anything will help please

Mathematics
1 answer:
Bumek [7]3 years ago
4 0

Answer: 1, 2, 4, or 5

Step-by-step explanation:

The relationship in #3 is a function because all the x values are distinct, that is, none are repeated. (Y values don't matter.)

A function will not repeat any x values so if your goal is for the relationship in #4 to NOT be a function, repeat one of the x values. Any one will work.

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Alchen [17]
So probability is (disred outcomes) divided by (total possible outomces

so
hearts and clubs are 2 out of 4 total suits and since there are the same number of cards per suit, it simplifies
2=desrired oucomes
4=total possible
2/4=1/2=0.5=50%

answer is 1/2 or 0.5 or 50%
6 0
3 years ago
What is the answer to 3/7+2/7
Ad libitum [116K]
5/7 is your answers
7 0
4 years ago
Find the exact solution for the following system of equations. 2x+3y=48 x+6y=11
TEA [102]
Question <span>2x+3y=48
Answer </span><span>x = 24 + -1.5y

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4 0
3 years ago
Help I’m not sure with this one!! Urgent help
Nastasia [14]

This system has exactly one solution, because the two equation are linearly independent (i.e. one is not a multiple of the other).

We can explicitly find the solutions: from the first equation we deduce

x = \dfrac{c-by}{a}

Plug this value for x in the second equation:

\dfrac{a}{3}\cdot \dfrac{c-by}{a}+\dfrac{by}{2}=\dfrac{c}{6} \iff \dfrac{c-by}{3}+\dfrac{by}{2}=\dfrac{c}{6} \iff \dfrac{2(c-by)+3by}{6}=\dfrac{c}{6}

Multiply both sides by 6 to get

2(c-by)+3by=c \iff 2c-2by+3by=c \iff by=-c \iff y=-\dfrac{c}{b}

Plug this value for y in the expression for x:

x = \dfrac{c-by}{a} = \dfrac{c-b\cdot\frac{-c}{b}}{a}=\dfrac{2c}{a}

Since both a,b are not zero, both solutions are well defined.

8 0
3 years ago
What is an equation of the line that passes through the points (-4, 2) and (-8, -3)
Nadusha1986 [10]

Answer:

a line through (-4,2) and (-8,-3) has slope = (2+3)/(-4+8) = 5/4 = (y-2)/(x+4)

cross multiply

5x +20 = 4y-8

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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