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Mnenie [13.5K]
3 years ago
9

I dont get this, its really difficult

Mathematics
2 answers:
Anarel [89]3 years ago
8 0
You add the previous 2 numbers so the answer would be 162
Alex777 [14]3 years ago
8 0
You have to look at the three numbers before it....and you just add the last three numbers together.Just like the first three numbers = 3 



the anwser is 193     =*)
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Juang has completed 80% of his homework. He has finished 12 problems. How many questions are on his homework?
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15 or 20

Step-by-step explanation:

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What is the missing number in the equivalent fraction? 3/4=?/8
barxatty [35]

Answer:

6/8

Step-by-step explanation:

3?4=.75

6/8=.75

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What’s x please help ASAP
mezya [45]

Answer:

x = 9

Step-by-step explanation:

You have to use the Secant Segment theorem:

AB * AC = AD * AE

This means that the external piece of the secant times the whole secant for one is equal to the external piece of the secant times the whole secant for the other.

Now, setup an equation:

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3 years ago
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What’s the slope of this chart?
weqwewe [10]
The slope is 9
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8 0
3 years ago
Fifteen telephones have just been received at an authorized service center. Five of these telephones are cellular, five are cord
viktelen [127]

Answer:

a) The probability of getting all (five) cordless phones among the first 10 is 0.0839.

b) The probability of having exactly two types in the last five is 0.24975.

c) To pick a sample of size 6 which contains two of each type of phone. The probability of selecting 2 phones from each type is 0.199800.

Step-by-step explanation:

a)  The first ten serviced (without regard to order within the first ten) constitute a random sample without replacement of size 10 from 15 phones.

So, such samples are:                  (Using Combination  "C")

                  (15C10) =3003\\

We now regard the phones as of just two types: cordless or not-cordless. The not-cordless phones are the cellular and regular phones, and there are 10 such phones.

So, The number of ways to pick 5 cordless and 5 non-cordless is

                       (5C5) *\\ (10C5) =252

Thus the probability of getting all (five) cordless phones among the first 10 is

                                               \frac{252}{3003} =0.0839

b)  Regard the last 5 phones (without regard to order within the last 5) as a sample with replacement from the 15 phones.There are (15C5) such samples.

Thus

There are (3C2)= 3 ways to choose the two types. For each such choice there are (10C5)= 252 possible ways to get a sample of size 5 from only these two types of phones.

also as the 2 of these samples contain all phones of same type so,

                                                 252-2 = 250

250 ways are to pick from these two types, having both type restricted.

then the probability will be

                                               \frac{3*(250)}{15C5} =0.249756

c)  We want to the find the probability that two phones of each type are among the first six serviced. The first six serviced can be regarded, when ignoring the order among the first 6, as an unordered sample of size 6 from 15 objects. so, there are (15C6) samples.

And there are (15C2)^3 ways to pick from each 3 types of phones.

Thus the probability of selecting such a sample is

                                              \frac{(15C2)^2}{(15C6)}=0.199800

7 0
3 years ago
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