What value of x makes the equation 7x-2(3x+1)=4x-(3-x)-19 true?

Solve for u. 11u = -22 Simplify your answer as much as possible. <3 u = ???

lawyer [7]

Answer:

u=-2

Step-by-step explanation:

Let's solve your equation step-by-step.

11u=−22

Step 1: Divide both sides by 11.

11u

11

=

−22

11

u=−2

Answer:

u=−2

4 0

3 years ago

Add (13x – 4) and (–6x + 15)

kompoz [17]

(13x – 4) + (–6x + 15) =

13x - 4 - 6x + 15 =

7x + 11

4 0

3 years ago

Graph g is a translation of the graph of y= sin x (dashed line).a) write down the equation of g b) write down the coordinates of

labwork [276]

Answer:

a) $G(x)= \sin x + 2$

b) The coordinates of P are

$\displaystyle \left( \frac{3\pi}{2},1\right)$

Step-by-step explanation:

Translation

The dashed line shows the graph of the function

$y = \sin x$

This function has a maximum value of 1, a minimum value of -1, and a center value of 0.

a)

Graph G shows the same function but translated by 2 units up, thus the equation of G is:

$\boxed{G(x)= \sin x + 2}$

b) The coordinates of P correspond to the value of

$x = \frac{3\pi}{2}$

The value of G is

$\displaystyle G(\frac{3\pi}{2})= \sin \frac{3\pi}{2} + 2$

Since

$\sin \frac{3\pi}{2}=-1$

$\displaystyle G(\frac{3\pi}{2})= -1+ 2=1$

The coordinates of P are

$\displaystyle \left( \frac{3\pi}{2},1\right)$

8 0

2 years ago

X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y

andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

$\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}$

Part b.

Consider V(3X + 2Y)

$\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}$

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

$3 X+2 Y \sim N(18,77)$

Thus,

$P(3 X+2 Y < 18)=0.5$

Part d.

Consider P(3X + 2Y < 28)

$Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}$

$\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}$

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0

1 year ago

What single percentage change is equivalent to a 11% increase followed by a 15% increase?

AlekseyPX

Answer:

It's a total increase by 27,65%

Step-by-step explanation:

1,11 × 1,15 = 1,2765

1,2765 = +27,65%

7 0

2 years ago