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Licemer1 [7]
3 years ago
13

If LJK ~ PQN, find x.

Mathematics
2 answers:
mixer [17]3 years ago
7 0
Here is x I found it.
spayn [35]3 years ago
4 0

Answer:

x = 33

Step-by-step explanation:

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What’s the class width
aksik [14]

Answer:

4

Step-by-step explanation:

Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:

CW = UCL - LCL

Where,

CW= Class width

UCL= Upper class limit

LCL= Lower class limit

From the table above:

For class 1, CW = 64 - 60 = 4

For class 2, CW = 69 - 65 = 4

For class 3, CW = 74 - 70 = 4

For class 4, CW = 79 - 75 = 4

For class 5, CW = 84 - 80 = 4

Therefore, the class width of the grouped data = 4

6 0
3 years ago
What is the solution to -3/4x
zubka84 [21]

Answer:

3x/4

Step-by-step explanation:

that's what I found. It would be better if u had more details in your question.

5 0
3 years ago
What additional information is needed to prove the triangles are congruent by the SAS Postulate?
Kitty [74]
You need to know the length of two sides and the degree of one angle.
7 0
4 years ago
The perimeter of a rectangular park is 300 feet. The length of the park is 50 feet longer than the width.
bixtya [17]

Answer:

85 feet

Step-by-step explanation:

P=2L+2W where L is the length and W is the width. If the length is 50 feet longer than the width, we can write the expression L=50+W. Substituting into P=2L+2W we get P=2(50+W)+2W=100+2W+2W=100+4W. Since P=300, we can say 300=100+4W. Subtracting 100 from each side we get 200=4W. Dividing each side by 4 gives 50=W. Substituting this into L=50+W gives L=50+35=85. The length is 85 feet.

3 0
3 years ago
Find the area of the regular polygon 7 in​
nata0808 [166]

Ummmm that’s a triangle but I guess I’ll solve for both 7x7= 49/2= 24.5 triangle. Polygon is different but I guess if the perimeter and line to the center is both 7 okay 7x5= 35x7= 245/2= 122.5 cause triangle is wxL /2 and polygon is AxP/2 soooo I hope this helped

4 0
3 years ago
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