Answer:
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
That is z with a pvalue of 
, so Z = 1.645.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.
The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Mya should put 3/5 in each serving.
Answer:
Reminder that is this form a(b)^x where a > 0
When b > 0 but < 1 that is a decay function
When b > 1 than its a growth function
Step-by-step explanation:
So following this you can figure out the answer
g(x)=0.3(x)
this is neither since there is no exponent (linear)
H=72(56)^t
this is growth since b = 56
A=(43)^t
this is growth since b = 43 ("a" is understood as "1")
H=5.9(0.82)^t
this is decay since b = 0.82
y=0.8(3.6)^t
this is growth since b = 3.6
f(t)=0.72(15)^t
this is growth since b = 14
A=49(8)^t
this is growth since b = 8
Answer:
4 months
Step-by-step explanation:
(2000 *6)/100 = 120
120x = 480
X = 480/120
X = 4 months
