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tamaranim1 [39]

4 years ago

13

Group 1, period 7 element

2 answers:

Serhud [2]4 years ago

8 0

Answer:

Period 7 element

Hydrogen

Lithium Beryllium Fluorine

Sodium Magnesium Chlorine

Potassium Calcium Bromine

Rubidium Strontium Iodine

Explanation:

Jet001 [13]4 years ago

8 0

Answer:

Group 1 a period 7 element is francium (Fr)

Explanation:

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What is the electron configuration silver, Ag? exeception

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3 years ago

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

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$[H^{+}]$ = $1.64 \times 10^{-6}$

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3 years ago

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Shtirlitz [24]

The answer is A
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3 years ago

Read 2 more answers