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anzhelika [568]
3 years ago
5

A catalyst lowers the activation energy for both the forward and the reverse reactions in an equilibrium system, so it has no ef

fect on the equilibrium position of a system. True False
Chemistry
1 answer:
Art [367]3 years ago
4 0
<h2>Answer:</h2>

<u>The statement is </u><u>true</u>

<h2>Explanation:</h2>

When we add a catalyst to a system, both the forward and reverse reaction rates will speed up equally at the same time thereby allowing the system to reach equilibrium faster. But one thing that is very important to keep in mind that the addition of a catalyst has no effect on the final equilibrium position of the reaction because it only makes the reaction faster and nothing else.

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Assessment started: undefined.
Bingel [31]

Answer:

Reactivity

Explanation:

Examples of chemical properties includes toxicity, acidity, reactivity and heat of combustion

8 0
4 years ago
Read 2 more answers
To 100.0 g water at 25.00 ºc in a well-insulated container is added a block of aluminum initially at 100.0 ºc. the temperature o
11111nata11111 [884]
When the amount of heat gained = the amount of heat loss

so, M*C*ΔTloses = M*C* ΔT gained

when here the water is gained heat as the Ti = 25°C and Tf= 28°C so it gains more heat.

∴( M * C * ΔT )W = (M*C*ΔT) Al

when Mw is the mass of water = 100 g 

and C the specific heat capacity of water = 4.18

and ΔT the change in temperature for water= 28-25 = 3 ° C

and ΔT the change in temperature for Al = 100-28= 72°C

and M Al is the mass of Al block

C is the specific heat capacity of the block = 0.9 

so by substitution:

100 g * 4.18*3 = M Al * 0.9*72

∴ the mass of Al block is = 100 g *4.18 / 0.9*72

                                          = 19.35 g 





4 0
3 years ago
Which formula can represent hydrogen ions in an aqueous solution?
faltersainse [42]

Answer:

H30+(aq)

Explanation:

im almost postive this is correct ,but if not its OH-(aq)

6 0
3 years ago
Select true or false: if the ph of pure water is 7.0, the hydroxide ion concentration in pure water is 1 × 10–7 m.
Vedmedyk [2.9K]

Answer:

True

Explanation:

as the ph of pure water is 7

(-)log(10^-7) = 7

7 0
3 years ago
Experiment #1A melting point of an old sample of Naphthalene was completed and a melting range of 77-83 oC was observed and reco
White raven [17]

Answer:

%error = 0.32%

Explanation:

Let's answer both questions, by parts.

1. Percentage error:

In this case, I do not have the video, but I do have the reported melting point of naphtalene which is 80.26 °C.

The expression to calculate the percentage error is the following:

%Error = absolute error / actual percentage. (1)

And the absolute error is:

Abs error = actual value - experimental value  (2)

But the experimental value is a range, so we just have to get a average of that:

Exp value = 77 + 83 / 2 = 80 °C

Now the absolute error:

Abs error = 80.26 - 80 = 0.26 °C

Finally the %error:

%error = (0.26 / 80.26) * 100

<h2>%error = 0.32%</h2>

2. Meaning of melting point range and %error

The melting point range just means that the sample of naphtalene has impurities, and when a sample of any compound has impurities, melting point tends to be low. However, this decrease of temperature is a wider range. But usually a range of just 5° C means that compound has little traces of impurities but it can still be used for reactions.

The %error means that the impurities of the sample are really low, so the sample is practically pure with little traces of impurities.

3 0
3 years ago
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