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Over [174]
4 years ago
9

Please help me with this geometry question!

Mathematics
1 answer:
borishaifa [10]4 years ago
3 0
Not gonna lie forgot the actual answer but use sin, cos, and tan.
sin=opposite/hypotenuse
cos=adjacent/hypotenuse
tan=opposite/adjacent
You might be interested in
Which equation can be used to find the surface area of the cylinder?
UNO [17]

Answer:

Step-by-step explanation:

SA= 2*r*r*pi + 2*pi*r*h

   = 2*6*6*3.14 + 2*3.14*6*8

4 0
3 years ago
An article in USA Today stated that Internal surveys paid for by directory assistance providers show that even the most accurate
MariettaO [177]

Answer:

a. 11.26 % b. 6.76 %. It appears so since 6.76 % ≠ 15 %

Step-by-step explanation:

a. This is a binomial probability.

Let q = probability of giving out wrong number = 15 % = 0.15

p = probability of not giving out wrong number = 1 - q = 1 - 0.15 = 0.75

For a binomial probability, P(x) = ⁿCₓqˣpⁿ⁻ˣ. With n = 10 and x = 1, the probability of getting a number wrong P(x = 1) = ¹⁰C₁q¹p¹⁰⁻¹

= 10(0.15)(0.75)⁹

= 1.5(0.0751)

= 0.1126

= 11.26 %

b. At most one wrong is P(x ≤ 1) = P(0) + P(1)

= ¹⁰C₀q⁰p¹⁰⁻⁰ + ¹⁰C₁q¹p¹⁰⁻¹

= 1 × 1 × (0.75)¹⁰ + 10(0.15)(0.75)⁹

= 0.0563 + 0.01126

= 0.06756

= 6.756 %

≅ 6.76 %

Since the probability of at most one wrong number i got P(x ≤ 1) = 6.76 % ≠ 15 % the original probability of at most one are not equal, it thus appears that the original probability of 15 % is wrong.

3 0
3 years ago
How do you do this problem?
ra1l [238]

Step-by-step explanation:

∫ t⁷ e^(-t⁴) dt

If x = -t⁴, then dx = -4t³ dt, and ¼ x dx = t⁷ dt.

∫ ¼ x eˣ dx

If u = ¼ x, then du = ¼ dx.

If dv = eˣ dx, then v = eˣ.

∫ u dv = uv − ∫ v du

= ¼ x eˣ − ∫ ¼ eˣ dx

= ¼ x eˣ − ¼ eˣ + C

= ¼ eˣ (x − 1) + C

Substitute back:

= ¼ e^(-t⁴) (-t⁴ − 1) + C

7 0
3 years ago
Read 2 more answers
Hello could someone help me with one or two of these questions i don’t know, but thank you!
rjkz [21]
Anwser: 6



step by step explanation:
8 0
3 years ago
suppose that y and z are points on a number line if y z equals 16 + y lies at -4 where could z be located
Masteriza [31]

<u>Corrected Question</u>

Suppose that y and z are points on a number line if yz equals 16 and y lies at -4. Where could z be located?

Answer:

z would be located at -4.

Step-by-step explanation:

If the product of y and z, yz=16

Point y lies at -4.

Substituting y=-4 into yz=16, we obtain:

-4z=16

Divide both sides by -4

z=-4

Therefore, <u>z would be located at -4</u>, which is the same point at which y is located.

y and z are the same points on the number line.

We know our result is correct because the product of two negative numbers is positive.

7 0
4 years ago
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