Can someone plz teach me step by step, how to do this?

what is the perimeter of the triangle. i do not know how to start this problem. any help will be greatly appreciated :))

xz_007 [3.2K]

Given:

Point F,G,H are midpoints of the sides of the triangle CDE.

$FG=9,GH=7,CD=24$

To find:

The perimeter of the triangle CDE.

Solution:

According to the triangle mid-segment theorem, the length of the mid-segment of a triangle is always half of the base of the triangle.

FG is mid-segment and DE is base. So, by using triangle mid-segment theorem, we get

$\dfrac{1}{2}DE=FG$

$DE=2(FG)$

$DE=2(9)$

$DE=18$

GH is mid-segment and CE is base. So, by using triangle mid-segment theorem, we get

$\dfrac{1}{2}CE=GH$

$CE=2(GH)$

$CE=2(7)$

$CE=14$

Now, the perimeter of the triangle CDE is:

$Perimeter=CD+DE+CE$

$Perimeter=24+18+14$

$Perimeter=56$

Therefore, the perimeter of the triangle CDE is 56 units.

7 0

3 years ago

Write an equivalent expression for 7 + 5 k minus 2 minus 3 k + n. Which statements are true about the steps for writing the equi

Nataly [62]

Answer:

1. Combine the constant terms by adding 7 and –2.

4. Combine the like variable terms by adding the coefficients

5. 5 k and negative 3 k are like variable terms

6.The constants 7 and –2 are like terms.

7. The equivalent expression is 5 + 2 k + n.

5 0

2 years ago

William and Debra Pierce are celebrating their 20th anniversary by having a reception at a local reception hall. They have budge

erica [24]

The greatest number of people that William and Debra may invite and still stay within their budget is 63.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Since William and Debra have budgeted $2,500 for their reception. Therefore, their total expenses should be equal to the total expenses in the reception.

Budget = Total expenses

Budget = Reception hall Cleanup charge + $38 per person fee

Let the number of people invited to the party be represented by x,

$2,500 = $100 + $38(x)

2500 = 100 + 38x

2500 - 100 = 38x

2400 = 38x

x = 2400 / 38

x = 63.157 ≈ 63

Hence, the greatest number of people that William and Debra may invite and still stay within their budget is 63.

Learn more about Equation here:

brainly.com/question/14686792

#SPJ1

5 0

1 year ago

Solve the equation 14=7(2x-4) using two different methods. Show your work. Which method do you prefer? Explain. need help thanks

Jet001 [13]

Answer:

x=3

Step-by-step explanation:

14=7(2x-4)

14/7=2x-4

2=2x-4

2x=2+4

2x=6

x=6/2

x=3

------------

14=7(2x-4)

14=14x-28

14x=14+28

14x=42

x=42/14

x=3

5 0

3 years ago

Read 2 more answers

Anybody who knows Pre Calc?? My last offer here<br> Solution PLS!

4vir4ik [10]

Answers:

true speed = 26.935546 knots
true bearing = 102.265139 degrees

The values are approximate. Round them however you need to.

====================================================

Explanation:

The diagram you have drawn is correct if you're only considering one current. Specifically current #1 which has the bearing of 290 degrees moving at 25 knots.

The red angle is 290 degrees. The remaining portion that is needed to get a full 360 degrees is 360-290 = 70. This adds to the blue portion in quadrant 1, which is 90, and we get 70+90 = 160. So the blue angle is 160 degrees.

The vector for current #1 is <25*cos(160), 25*sin(160)>

This approximates to <-23.4923155, 8.5505036>

All of this is for current #1.

------------

Vector #2 is much more simple in terms that there aren't messy decimal approximations here. The direction is due north, which means that the vector is pointing straight up toward 90 degrees.

We can then say: <12*cos(90), 12*sin(90)> = <12*0, 12*1> = <0, 12>

Vector #2 is <0,12>

When you wrote <12,0>, you were on the right track, but you had the coordinates swapped in the wrong order.

----------

Then we have to account for a wind going 4 knots in the southwest direction. This is at the angle 225 degrees (we rotate 180 degrees plus another 45 to get 225). So,

vector #3 = <4*cos(225), 4*sin(225)> = <-2.8284271, -2.8284271>

This vector's coordinates are approximate

---------

To recap everything so far, vectors 1 through 3 are the following

p = <-23.4923155, 8.5505036>
q = <0, 12>
r = <-2.8284271, -2.8284271>

I'm using variables to represent the vectors at this point, so we can then add them up to get...

s = p+q+r

s = <-23.4923155, 8.5505036> + <0,12> + <-2.8284271, -2.8284271>

s = <-23.4923155+0+(-2.8284271), 8.5505036+0+(-2.8284271)>

s = <-26.3207426, 5.7220765>

Vector s represents the sum of the three vectors p, q, and r. The two currents and the wind ultimately combine together to push the boat in the direction and along the length of vector s.

----------------------

Now that we know the coordinates of vector s, we use them to find the true speed and true bearing of the boat.

speed = sqrt(a^2 + b^2)

speed = sqrt( (-26.3207426)^2 + (5.7220765)^2 )

speed = 26.935546 knots, which is approximate

angle = arctan(b/a)

angle = arctan(5.7220765/(-26.3207426))

angle = -12.265139

Add 360 to this angle to find that we get to the coterminal angle of -12.265139+360 = 347.734861 degrees

This angle is in quadrant 4, which is the southeast quadrant. If we rotate another 360-347.734861 = 12.265139 degrees, going counterclockwise, then we'll face directly east. Then another 90 degree counterclockwise rotation has us face directly north.

In total, the true bearing is approximately 90+12.265139 = 102.265139 degrees

So we'll start aiming north, and then rotate roughly 102.265139 degrees toward the east to get to the true bearing.

4 0

3 years ago