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s2008m [1.1K]
3 years ago
9

A menu in a restaurant allows you to pick some items from Column A and some from Column B. Column A has 24 items. Column B has 1

6 items. If you and 3 friends want to order everything from both columns, but not order any item more than once, how many items from each column would you each choose (assuming each person orders the same number of items from each column)?
Mathematics
1 answer:
Darya [45]3 years ago
5 0
You can each order from: Column A- 6 times, Column B- 4 times
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(a + b - c )(a + b + c )
True [87]

If you are looking for the expanded version, this is it. It is also possible to group either an a from (a^2 + 2b) or a b from (2ab + b^2). Hope this helps!

6 0
3 years ago
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Buthaina babysat nine times. She earned 15, 20,10,12, 20,16, 80, and 18 dollars for eight of the babysitting jobs. How much did
bija089 [108]

Answer:

216

according to 9*mean(24)

Step-by-step explanation:

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3 years ago
3n-7/6=2n+5/3<br><br> solve for n please
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N = 17/6
or
2.83 (3 is repeating)
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3 years ago
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________________________
xenn [34]

✩ Answer:

 ✧・゚: *✧・゚:*✧・゚: *✧・゚:*✧・゚: *✧・゚:*  

 \bold{Hello!}\\\bold{Your~answer~is~below!}  

✩ Step-by-step explanation:

 ✧・゚: *✧・゚:*✧・゚: *✧・゚:*✧・゚: *✧・゚:*

✺ Divide both sides by −3. Since −3 is negative, the inequality direction is changed:

  • -3 ÷ -3 = Cancels Out
  • Turns into: \frac{-9}{-3} >5x-2

✺ Divide −9 by −3 to get 3. Since they are both negatives it turns into a positive:

  • -9 ÷ -3 = 3
  • Turns into: 3 > 5x - 2

✺ Swap sides so that all variable terms are on the left hand side. This changes the sign direction once more:

  • Turns into: 5x-2

✺ Add 2 to both sides:

  • Turns into: 5x

✺ Add 3 and 2 to get 5:

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✺ Divide both sides by 5. Since 5 is positive, the inequality direction remains the same:

  • 5 ÷ 5 = Cancels Out
  • Turns into: x

✺ Divide 5 by 5 to get 1:

  • 5 ÷ 5 = 1

✺  So your answer is B, \boxed{x.

(Number line is below.)

Hope~this~helps~and,\\Best~of~luck!\\\\~~~~~-TotallyNotTrillex

5 0
2 years ago
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What is the factored form of x^3-1
polet [3.4K]

Answer:

the factors of x^3-1 are x^3 -1 = (x-1) (x^2 +x+1)\\

Step-by-step explanation:

We need to find factors of x^3 -1

x^3-1 \\(x)^3 -(1)^3\\We \,\, know\,\, a^3 -b^3 = (a-b) (a^2 +ab + y^2) \\So, \,\, using\,\, the \,\, formula\,\,\\Here\,\, a= x \,\,and\,\, b= 1\\(x)^3 -(1)^3 = (x-1) (x^2 +x+1)\\

So, the factors of x^3-1 are x^3 -1 = (x-1) (x^2 +x+1)\\

7 0
3 years ago
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