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3 years ago

I keep getting this wrong and I only have one chance to get it right. Please help! It's timed aswell.

Mathematics

1 answer:

allsm [11]3 years ago

7 0

PIC 1 - floor function

PIC 2 - 1,1

PIC 3 - -1,1

PIC 4 - f(x)=[1/2]

PIC 5 - f(x)=1/5

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Derek is solving the following equation. Find where he made a mistake.

Arisa [49]

Answer:

he was supposed to add three on both sides

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3 years ago

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We are in school 9 months out of the year. What percent of the year are we in<br> school?

Igoryamba

There are 12 months in a year.

Divide 9 by 12 then multiply by 100 to get the percentage.

9/12 = 0.75 x 100 = 75%

Answer: 75%

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2 years ago

Indicate below whether the equation in the box is true or false 1/6 = to 6/12

Vitek1552 [10]

Answer: 1/6 is not equal to 6/12 because 6/12 is 1/2 and 1/6 is less

Step-by-step explanation:

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3 years ago

A diving board is 10 feet above the surface of the water. At time t = 0, the board propels Chris upward at a rate of 12 feet per

Art [367]

Answer:

Chris will take 0.75 seconds to return to his starting height of 10 feet.

Step-by-step explanation:

Let the height of Chris be represented by $h(t) = -16\cdot t^{2}+12\cdot t +10$ , where $h(t)$ is the height in feet and $t$ , the time in seconds. First, we equalize the formula to a height of 10 feet and simplify the resulting expression, that is:

$-16\cdot t^{2}+12\cdot t +10 = 10$

$-16\cdot t^{2}+12\cdot t = 0$

Then, we simplify the expression by algebraic means:

$-16\cdot t\cdot \left(t-\frac{3}{4} \right) = 0$

Roots of the polynomial are, respectively:

$t = 0\,s\,\lor \,t = 0.75\,s$

First root represents the initial height of Chris, whereas the second one represents the instant when Christ returns to the same height above the surface of the water. Hence, Chris will take 0.75 seconds to return to his starting height of 10 feet.

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3 years ago

Simplify 3z + 4z +4 -2 -5z when Z=8

Ber [7]

Answer:

Step-by-step explanation:

3z + 4z +4 -2 -5z

Combine like terms

3z + 4z -5z +4-2

2z+2

Let z=8

2*8 +2

16+2

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4 years ago

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