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2 years ago

4. In a scale drawing, the length of a

Mathematics

2 answers:

skad [1K]2 years ago

5 0

Answer:

1ft=.33in

Step-by-step explanation:

For every 1ft in the room its .33 on paper.

.33333333333333333333333333333x18=6

mr Goodwill [35]2 years ago

3 0

Answer:

For every 1 inch on the drawing, it's 3 feet in real life.

Step-by-step explanation:

First, consider the length. The length is 6 inches on the drawing, while in actuality it is 18 feet. So every 6 inches represents 18 feet. Let's make a ratio; 6 : 18. To simplify it, divide both sides by 6; 6 : 18 = 1 : 3.

For every 1 inch on the drawing, it's 3 feet in real life.

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Determine the slope-intercept form of the equation of the line parallel to y = x + 11 that passes through the point (–6, 2).

MArishka [77]

Line parallel to y=x+11 so slopes are equal then
y= x+b
Passing through the point C (-6;2) then C belongs to this line
yc=xc+b
b= 6+2
b= 8
So y intercept is equal to 8

3 0

2 years ago

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(8+2b)+(-4+6x)+(6+9m)

ANTONII [103]

Answer:

2 b + 9 m + 6 x + 10

Step-by-step explanation:

2 b + 4 + 6 x + 6 +9 m

2 b + 6 x + 10 + 9m

2 b + 6 x + 9 m + 10

= 2 b + 9 m + 6 x + 10

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2 years ago

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Here is a triangular pyramid and its net.

bazaltina [42]

Answer:

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. $\text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\$