How to get 6/9 as a decimal using division help

ohaa [14]

Answer:

true 7/8 is a rational number

6 0

2 years ago

Which of the following fractions have repeating decimal representations? Which have terminating decimal representations?

natali 33 [55]

Repeating decimal representation will be 3/13, 7/24. Terminating decimal representation will be 3/16, 4/125.

<h3>What is decimal?</h3>

The accepted method for representing both integer and non-integer numbers is the decimal numeral system. It is the expansion of the Hindu-Arabic numeral system to non-integer values. Decimal notation is the term used to describe the method of representing numbers in the decimal system. The base-10 number system, arguably the most widely used number system, is referred to as decimal. The decimal number system consists of ten single-digit numbers: 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9. The number following nine is 10.

Here,

Repeating decimal representation,

=3/13, 7/24

Terminating decimal representation,

=3/16, 4/125

3/13 and 7/24 will be repeated in decimal form. The final two decimal places are 3/16 and 4/125.

To know more about decimal,

brainly.com/question/25903211

#SPJ1

7 0

1 year ago

I seem to be confused can anyone please help

Genrish500 [490]

Use photo math :>some helpful info

6 0

2 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago

What does x equal in the equation -6x +10x = 20?

Sliva [168]

Answer:

5

Step-by-step explanation:

-6x +10x = 20

4x=20

x=20/4

x=5

3 0

2 years ago