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Phoenix [80]
3 years ago
6

What is the common difference of the arithmetic sequence 5 8 11 14

Mathematics
2 answers:
Brums [2.3K]3 years ago
8 0

Answer:

3

Step-by-step explanation:

The gap between every single number of this sequence is 3.

14 - 11 = 3

8 - 5 = 3

This gap is called the common difference. You can find it by subtracting values in the sequence that are next to each other.

Ket [755]3 years ago
6 0
The answer is for sure 3
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A cake recipe says to bake the cake until the center is 180 degrees F, then let the cake cool to 110 degrees F. The table shows
Kobotan [32]

Answer:

Check the explanation

Step-by-step explanation:

a) The following exponential model would fit the given dataset : \small y = 129.122 \times (0.9742)^x

b) To cool down to 110 degrees, it would take approximately 7.3 minutes based on the above model.

8 0
3 years ago
Which of the following statements is true?
bogdanovich [222]

Answer:

(0,0) is a solution to n=m and n=4m

Step-by-step explanation:

For the first equation, If u insert 0 as m into n=m

n=(0) then n will equal 0.

For the second equation, if u insert 0 as m in n=4m

n=4(0) then n will also equal 0.

So the answer is (0,0) is a solution to n=m and to n=4m

Hope this helps :)

3 0
3 years ago
Need help please thanks
olchik [2.2K]

Answer:

C

Step-by-step explanation:

All angles in a triangle add up to 180°.

63 + 52 = 115°.

180 - 115 = 65°, so part of the answer is done, y = 65°.

The angle next to <em>y </em>is a vertical angle.

61 + 65 = 126°.

180 - 126 = 54°.

So, x = 54°, y = 65°.

6 0
4 years ago
Can someone please help me on exercise 1.6, #2 (a to e). *Will report any spam answers* Thank you!
g100num [7]

As shown in the picture, I sent two pictures.

7 0
3 years ago
A loan of 43,000 is made of 4% interest, compounded annually. After how many years will the amount due reach $66,000 or more?
Charra [1.4K]

Answer:

10 yrs

Step-by-step explanation:

A=P(1+r/n)^nt, P=initial investment, r=annual interest rate,n=number of compounding periods per year, A=amount after t years

For given problem:

P=37000

r=5.5%=.055

n=1

A=62000

..

62000=37000(1+.055)^t

62/37=1.055^t

tlog(1.055)=log(62/37)

Using log keys on calculator:

t=log(62/37)/log(1.055)≈10 yrs

3 0
3 years ago
Read 2 more answers
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