Here is the full question
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
Equation:
y=-16x^2+153x+98
Answer:
10.2 seconds
Step-by-step explanation:
Given equation : 
 shown the expression of a quadratic equation
 shown the expression of a quadratic equation
Let y =0
∴
0 = 
where;

Using the quadratic formula:

replacing it with our values; we have:

 OR
    OR     
 OR
   OR     
Hence, we go by the positive value since,  is the time that the rocket will hit the ground.
x= 10.17
x = ≅ 10.2 seconds
Therefore, the rocket will hit the ground,  to the nearest 100th of second.  = 10.2 seconds