Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula, 
= a + (n-1)d
here, is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Answer:
The answer is 54 9/14
Step-by-step explanation:
what u do is this
#1. 765 divided by 14 which equals 54.64285714. Don't worry about the numbers after the decimal.
Then u do 65-54= 9 so u have 54 9/14
to check yourself just do 14 times 54= 756 + 9 = 765
Answer:
Coefficient
Step-by-step explanation:
-Usually a combination of variables and constants are multiplied to get a product.
-The constant or number part in the multiplication process is called the Coefficient
3x -4 (5 - x) = 7x -20
3x-20+4x=7x-20
7x-20=7x-20
