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lidiya [134]
3 years ago
6

What are zeroes of f(x) =x^2-x-2

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0
You have to factor this...
 So you have started with this...

x²-x-2=0
If you factor this you will get

(x+1)(x-2)=0

This gives you two solutions...
x=-1, x=2
Hope this helps! Give me a five-rate and a thanks!
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For what values of a are the following expressions true?/a+5/=-5-a
katovenus [111]

Explanation:

The expression is given below as

|a+5|=-5-a

Concept:

We will apply the bsolute rule below

\begin{gathered} if|u|=a,a>0 \\ then,u=a,u=-a \end{gathered}

By applying the concept, we will have

\begin{gathered} \lvert a+5\rvert=-5-a \\ a+5=-5-a,a+5=5+a \\ a+a=-5-5,a-a=5-5 \\ 2a=-10,0=0 \\ \frac{2a}{2}=\frac{-10}{2},0=0 \\ a=-5,0=0 \end{gathered}

Hence,

The final answer is

a\leq-5

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11 months ago
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Answer:

P(x>12) = 0

Step-by-step explanation:

Given

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Required

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P(x > 12) = \frac{n(x > 12)}{n(x)}

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So:

P(x > 12) =\frac{0}{12}

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castortr0y [4]
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