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IRISSAK [1]
3 years ago
9

Find the Unit Rate: If 10 30.5 oz containers cost $70 how much does one container cost?​

Mathematics
2 answers:
Fantom [35]3 years ago
7 0

Answer: $7.00

One container would cost $7 because if you can buy 10 for $70 you would have to solve

\frac{70}{10}

Which equals $7.00

Please mark brainliest if correct :)

sleet_krkn [62]3 years ago
4 0

Answer:

$7

Step-by-step explanation:

70 / 10 = 7

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Varvara68 [4.7K]
2A) first find the measure of the angle above the right angle (180-122=58) so it equals 58°, while the right angle is obviously 90°. the whole triangle should be 180° so 90+58= 148. now we subtract this from 180 to get the measure for x. 180-148=32.

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3 0
3 years ago
For a special sale, a mens tie buyer plans to promote a $39.99 tie. Consequently, the buyer purchases 450 ties and wants to achi
zlopas [31]

Answer:

The average cost of each tie is $56.350

Step-by-step explanation:

We are given that a men tie buyer plans to promote a $39.99 tie. Consequently, the buyer purchases 450 ties

So, Cost of 450 ties = 450 \times 39.99=17995.5

An order for 100 ties that cost $20.00 each

Cost of 100 ties = 100 \times 20 = 2000

Total cost price = 17995.5+2000 = 19995.5

Let the selling price of 1 tie be x

Total ties = 450+100 = 550

So, SP of 550 ties =550x

Now we are given that markup is 55%

So, Profit % = 55%

So, CP = \frac{SP \times 100}{100+P\%}

Substitute the values

19995.5 = \frac{550x \times 100}{100+55}

19995.5 = \frac{550x \times 100}{155}

19995.5 \times 155 = 55000x

\frac{19995.5 \times 155}{55000}=x

56.350=x

Hence The average cost of each tie is $56.350

7 0
3 years ago
What is the Domain of the graph?, and What is the Range of the graph ? ​
Ronch [10]

Answer:

Domain is 0-12 and the range is 0-10

Step-by-step explanation:

The domain is the x values and the range is the y values

5 0
3 years ago
Read 2 more answers
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rosijanka [135]

Answer:

But there is no question. And the formula for the area of a triangle is 1/2bh not 1/2h.

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Answer:

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A -box 1

B -box 2

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3 years ago
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