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IRISSAK [1]
2 years ago
9

Find the Unit Rate: If 10 30.5 oz containers cost $70 how much does one container cost?​

Mathematics
2 answers:
Fantom [35]2 years ago
7 0

Answer: $7.00

One container would cost $7 because if you can buy 10 for $70 you would have to solve

\frac{70}{10}

Which equals $7.00

Please mark brainliest if correct :)

sleet_krkn [62]2 years ago
4 0

Answer:

$7

Step-by-step explanation:

70 / 10 = 7

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2) COMPOUND INTEREST If $22,000 is invested at an annual
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0,266666666667

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2 years ago
Determine the intercepts of the line.
Lilit [14]

Answer:

(-7.5, 0) x intercept

(0, 5.5) y intercept

Step-by-step explanation:

The x intercept is where it crosses the x axis

It crosses at (-7.5, 0)

The y intercept is where it crosses the y axis

It crosses at (0, 5.5)

5 0
3 years ago
Read 2 more answers
Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.
bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Substitute sin(\theta)=\frac{6}{11} into the first equation, solve for the cosine and simplify. Then, you obtain:

cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}

As sec\theta then cos\theta:

cos(\theta)=-\frac{\sqrt{85}}{11}

Now we can find tan\theta:

tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}

4 0
3 years ago
Read 2 more answers
If the x axis is positive and the y is zero what’s quadrant or axis is it in?
Alecsey [184]
Quadrant 1

Hope this helps!
Brainliest is much appreciated!
5 0
2 years ago
Read 2 more answers
Suppose customers in a hardware store are willing to buy​ N(p) boxes of nails at p dollars per​ box, as given by the following f
AleksAgata [21]

Answer:

a) -15 unites per dollar

b) -12 units per dollar

c) -18 units per dollar

Step-by-step explanation:

We are given the following in the question:

N(p) = 100-3p^2, 1\leq p \leq 4

where N(p) is the number of boxes of nails at p dollars per​ box.

a) average rate of change of demand for a change in price from ​$2 to ​$3.

Average rate of change =

\displaystyle\frac{N(3) -N(2)}{3-2}\\\\=\frac{100-3(3)^2-(100 - 3(2)^2)}{1}\\\\= -15\text{ units per dollar}

b) instantaneous rate of change of demand when the price is ​$2

Instantaneous rate =

N'(p) = \displaystyle\frac{d(N(p))}{dp} = -6p

N'(2) = -6(2) = -12

The instantaneous rate of change of demand when the price is ​$2 is decreasing at 12 units per dollar.

c) instantaneous rate of change of demand when the price is ​$3

Instantaneous rate =

N'(3) = -6(8) = -18

The instantaneous rate of change of demand when the price is ​$3 is decreasing at 18 units per dollar.

4 0
3 years ago
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