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Fofino [41]
3 years ago
8

How you do number 4 pls help

Mathematics
1 answer:
Artyom0805 [142]3 years ago
7 0

I haven't got a calculator right now but substitute the values into the cosine law so:

8² = 5² + c² - (2 x 5 x c x cos58)

and then use sine law to find B

sin58/8 = sinB/5

You might be interested in
F(x) = 3x + 1<br> f(2)=?
ANEK [815]

Answer: 7

Step-by-step explanation:

f(x) 3x+1

f(2) = 3(2) +1

f(2) = 6+1

     = 7

7 0
3 years ago
Please help !!
shutvik [7]

Given:

The limit problem is:

\lim_{x\to 3}(x^2+8x-2)

To find:

The limit of the function by using direct substitution.

Solution:

We have,

\lim_{x\to 3}(x^2+8x-2)

Applying limit, we get

\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2

\lim_{x\to 3}(x^2+8x-2)=9+24-2

\lim_{x\to 3}(x^2+8x-2)=33-2

\lim_{x\to 3}(x^2+8x-2)=31

Therefore, the correct option is D.

4 0
3 years ago
Which relationship is always true for the angles r, x, y, and z of triangle ABC?
mariarad [96]

That's the second one,


180 - x = r


Whenever two lines cross we get congruent opposite angles and supplemental adjacent angles, i.e. they add to 180 degrees.


The first one is almost right; we have r+y+z=180 and r+x=180 so x=y+z not quite what was written.


3 0
3 years ago
A line joins the point
Harrizon [31]

Intersection of the first two lines:

\begin{cases}5x - 2y + 3 = 0\\4x - 3y + 1 = 0\end{cases}

Multiply the first equation by 4 and the second by 5:

\begin{cases}20x - 8y + 12 = 0\\20x - 15y + 5 = 0\end{cases}

Subtract the two equations:

(20x - 8y + 12)-(20x - 15y + 5)=0 \iff 7y+7=0 \iff y=-1

Plug this value for y in one of the equation, for example the first:

5x - 2\cdot (-1) + 3 = 0\iff 5x+5=0 \iff x=-1

So, the first point of intersection is (-1,-1)

We can find the intersection of the other two lines in the same way: we start with

\begin{cases}x=y\\x=3y+4\end{cases}

Use the fact that x and y are the same to rewrite the second equation as

x=3x+4 \iff 2x=-4 \iff x=-2

And since x and y are the same, the second point is (-2, -2)

So, we're looking for a line passing through (-1,-1) and (-2, -2). We may use the formula to find the equation of a line knowing two of its points, but in this case it is very clear that both points have the same coordinates, so the line must be y=x

In the attached figure, line 5x - 2y + 3 = 0 is light green, line 4x - 3y + 1 = 0 is dark green, and their intersection is point A.

Simiarly, line x=y is red, line x = 3y + 4 is orange, and their intersection is B.

As you can see, the line connecting A and B is the red line itself.

5 0
3 years ago
please help i will mark brainliest, no spam answers i will report.
vovikov84 [41]

9514 1404 393

Answer:

  (c)  (3, 3)

Step-by-step explanation:

Point E partitions both the x-distance and the y-distance in the ratio 2 : 1. That is, for either the x-coordinates or the y-coordinates, ...

  CE : ED = 2 : 1

Try the answers with the x-coordinates.

  CE : ED = (1 -(-1)) : (5 - 1) = 2 : 4 . . . . incorrect

  CE : ED = (-3 -(-1)) : (5 -(-3)) = -2 : 8 . . . . incorrect

  CE : ED = (3 -(-1)) : (5 -3) = 4 : 2 = 2 : 1 . . . . correct

  CE : ED = (-1 -(-1)) : (5 -(-1)) = 0 : 6 . . . . incorrect

The only viable choice is (3, 3).

_____

<em>Alternate solution</em>

For a partitioning of m : n, the desired point is ...

  E = (n×C +m×D)/(m+n)

For partitioning of 2 : 1, the desired point is ...

  E = (1×(-1, -3) + 2×(5, 6))/(2+1) = (-1+10, -3 +12)/3

  E = (3, 3)

3 0
3 years ago
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